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diamong [38]
3 years ago
15

Find the equation of a line that intersects with y=2x-1 on the y-axis and is parallel to y=-x. Please explain.

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

so where does that line intersect the y axis? just plug in x=0 and you see y= -1. so (0, -1)

y = -x -1 is parallel because it has the same slope and goes through the right point

Gnesinka [82]3 years ago
5 0

Step-by-step explanation:

Hope it helps explain why and how to get the answer as well.

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What is the equation of the following line written in slope-intercept form?
nasty-shy [4]
SOLUTION:

To begin with, let's establish that the formula of this line is in slope-intercept form as follows:

y = mx

The formula for this line isn't:

y = mx + b

This is as this line doesn't have a y-intercept ( b ) as it passes through the origin instead. This means that ( b ) would be rendered useless in this formula as it would just bring us back to the y = mx formula as displayed below:

y = mx + b
y = mx + 0
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Moving on, for ( m ), we need to find the gradient of the line as displayed below:

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m = rise / run
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A. y = 5x
6 0
3 years ago
The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?
vovikov84 [41]

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
8 0
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Answer:

3√6

Explanation:

explanation is in the image above

HOPE THIS HELPS PLEASE MARK ME BRAINIEST

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2 years ago
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Answer:

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