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2 years ago

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What is the slope intercept form of the equation of the line passing through the point 2,-3 having a slope of m=-1/2?

1 answer:

Rudik [331]2 years ago

8 0

<span>what is the slope intercept form of the equation of the line passing through the point 2,-3 having a slope of m=-1/2?</span>

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HELP MARKING BRAINLIEST EXTRA POINTS !!

Scrat [10]

Answer:

The quadrilateral is a rectangle
$Perimeter=8\sqrt{2} \,\,Unit$
$Area=6\,\,sq.unit$

Step-by-step explanation:

Given,

$A=(0,0)\\B=(1,1)\\C=(4,-2)\\D=(3,-3)$

Now,

$Slope\,\,for\,\,AB=\frac{1-0}{1-0} =1\\\\Slope\,\,for\,\,CD=\frac{-3+2}{3-4} =1\\\\Slope\,\,for\,\,AD=\frac{-3-0}{3-0} =-1\\\\Slope\,\,for\,\,BC=\frac{-2-1}{4-1} =-1\\\\So,AB||CD\,\,and\,\,AD||BC$

$AB=\sqrt{(1-0)^2+(1-0)^2}=\sqrt{2}\\BC=\sqrt{(4-1)^2+(-2-1)^2}=3\sqrt{2}\\CD=\sqrt{(3-4)^2+(-3+2)^2}=\sqrt{2}\\AD=\sqrt{(3-0)^2+(-3-0)^2}=3\sqrt{2}\\\\So,\,\,AB=CD,AD=BC\\The\,\,quadrilateral\,\,is\,\,a\,\,rectangle$

$Perimeter=2*(AB+AD)=2*(BC+CD)\\=2*(\sqrt{2}+3\sqrt{2})=8\sqrt{2} \,\,Unit$

$Area=AB*AD=BC*CD=\sqrt{2} *3\sqrt{2}=6\,\,sq.unit$

Hope you have understood this.....

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if you liked it pls mark it as the brainliest

5 0

2 years ago

Find the coordinates of a point that divides the directed line segment PQ in the ratio 5:3. A) (2, 2) B) (4, 1) C) (–6, 6) D) (4

Yuri [45]

Answer:

The answer is explained below

Step-by-step explanation:

The question is not complete we need point P and point Q.

let us assume P is at (3,1) and Q is at (-2,4)

To find the coordinate of the point that divides a line segment PQ with point P at $(x_1,y_1)$ and point Q at $(x_2,y_2)$ in the proportion a:b, we use the formula:

$x-coordinate:\\\frac{a}{a+b}(x_2-x_1)+x_1 \\\\While \ for\ y-coordinate:\\\frac{a}{a+b}(y_2-y_1)+y_1$

line segment PQ is divided in the ratio 5:3 let us assume P is at (3,1) and Q is at (-2,4). Therefore:

$x-coordinate:\\\frac{5}{5+3}(-2-3)+3 \\\\While \ for\ y-coordinate:\\\frac{5}{5+3}(4-1)+1$

4 0

3 years ago

Rewrite the definition “All rectangles are parallelograms” in biconditional form.

harkovskaia [24]

In logic, a biconditional<span> is a compound </span>statement<span> formed by combining two conditionals under "and." Biconditionals are true when both </span>statements<span> (facts) have the exact same truth value.

It could help you transform the statement into biconditional form.

I hope my answer has come to your help. God bless you and have a nice day ahead!

</span>

5 0

2 years ago

Use the method of completing the square to write the equation of the given parabola in this form:

siniylev [52]

Formula is y = a(x-h)^2 + k

Where h is 1 and k is 1

f (x) = a(x-1)^2 + 1

-3 = a(0-1)^2 + 1

-3 = a(-1)^2 + 1

-3 = a(1) + 1

-3 - 1 = a

-4 = a

a = -4

A must be equal to -4

y = -4(x-1)^2 + 1

0 = -4(x-1)^2 + 1

4(x^2 - 2x + 1) - 1 = 0

4x^2 - 8x + 4 - 1 = 0

4x^2 - 8x + 3 = 0

4x^2 - 8x = -3

Divide fpr 4 each term of the equation....x^2 - 2x = -3/4

We must factor the perfect square ax^2 + bx + c which we don't have. We must follow the rule (b/2)^2 where b is -2....(-2/2)^2 = (-1)^2 = 1 and we add up that to both sides

x^2 - 2x + 1 = -3/4 + 1

x^2 - 2x + 1 = 1/4

(x-1)^2 = 1/4

square root both sides x-1 = (+/-) 1/2

x1 = +1/2 + 1 = 3/2

x2 = -1/2 + 1 = 1/2

x-intercepts are 1/2 and 3/2, in form (3/2,0); (1/2,0)

6 0

3 years ago

Read 2 more answers

Which expression can be used to find the surface area of the following square pyramid?

telo118 [61]

Answer:

Step-by-step explanation:

The slant height of one side of this pyramid is 5, and the base of this side is 4. Thus, the area of one slant side is (1/2)(5)(4) = 10 units^2.

There are 4 such sides. Thus, the total slant surface area is 4(10 units^2), or 40 units^2.

If you also want to include the base area, the total would be

40 units^2 + 16 units^2 = 56 units^2.

8 0

3 years ago