Round to 2 decimal places 0.607
1 answer:
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f(x) = (x + 7)² - 8
the equation of a quadratic in vertex form is
y = a(x - h)² + k
where (h, k ) are the coordinates of the vertex and a is a multiplier
given the quadratic in standard form : y = ax² + bx + c ( a ≠ 0 )
then the x-coordinate of the vertex is
= -
f(x) = x² + 14x + 41 is in standard form
with a = 1, b = 14 and c = 41
= -
= - 7
substitute this value into the equation for y- coordinate
y = (- 7 )² + 14(- 7 ) + 41 = 49 - 98 + 41 = - 8
f(x) = (x + 7)² - 8 ← in vertex form