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Hoochie [10]
3 years ago
11

Hey who ever can help me, I give 25 points

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
5 0

4x+2y=18

-2(2x+3y=15)=-4x-6y=-30

4x+2y=18

-4x-6y=-30

-4y=-12

y=3

2x+3(3)=15

2x+9=15

2x=6

x=3

(3,3)


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Which of the following is the endpoint of the altitude of a regular pyramid
larisa [96]
It’s either vertex or base
4 0
3 years ago
Al sumar y/o restar números decimales, siempre se debe aplicar la norma de los signos. * 1 punto FALSO VERDADERO
Luden [163]

Answer:

La norma de los signos es para el producto de números reales, y la norma es la siguiente.

(+)*(+) = (+)

(+)*(-) = (-)

(-)*(+) = (-)

(-)*(-) = (+)

Es decir, el producto de dos números de mismo signo es siempre positivo

El producto de dos números de distinto signo es siempre negativo.

Particularmente, para la suma esta norma no funciona (pues no está definida para la suma)

Pero en casos como:

5 - (-4)  

(esto sería: "la diferencia entre cinco y menos cuatro")

notar que podemos reescribir esto como:

5 + (-1)*(-4)

Ahora podemos aplicar la norma de los signos:

5 + 4 = 9

Donde aplicamos la norma de los signos,  

Podemos concluir que, si bien es una regla que aplica al producto, siempre la tenemos que tener en cuenta en cualquier operación que hagamos.

Por lo podemos concluir que la respuesta correcta es verdadero.

7 0
2 years ago
Assume that the national credit card interest rate is 12.83 percent. A study of 62 college students finds that their average int
meriva

Answer:

b)  95 percent confidence interval for this single-sample t test

[11.64, 16.36]

Step-by-step explanation:

Explanation:-

Given data  a study of 62 college students finds that their average interest rate is 14 percent with a standard deviation of 9.3 percent.

Sample size 'n' =62

sample mean x⁻ = 14  

sample standard deviation 'S' = 9.3

<u>95 percent confidence interval for this single-sample t test</u>

The values are (x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-}+t_{0.05}\frac{S}{\sqrt{n} })  the <u>95 percent confidence interval for the population mean  'μ'</u>

Degrees of freedom γ=n-1=62-1=61

t₀.₀₅ = 1.9996 at 61 degrees of freedom

(14 - 1.9996\frac{9.3}{\sqrt{62} } ,14+1.9996\frac{9.3}{\sqrt{62} })

(14-2.361 , 14 + 2.361)

[(11.64 , 16.36]

<u>Conclusion:-</u>

95 percent confidence interval for this single-sample t test

[11.64, 16.36]

<u></u>

6 0
3 years ago
Reflect the given preimage over y=−1 followed by y=−7. Find the new coordinates. What one transformation is this double reflecti
fenix001 [56]

Answer:

Reflecting over y = -1 line:

A'(8, -10)

B'(10, -8)

C'(2, -4)

Reflecting over y = -7 line:

A''(8, -4)

B'(10, -6)

C''(2, -10)

Step-by-step explanation:

Reflect the given preimage over y=−1 followed

by y=−7. Find the new coordinates. What one transformation is this double reflection the same as? (Note: when you are reflecting over a y= line, the x-values of the preimage will remain the same and you will be changing the y-values)

The coordinates of the preimage are:

A(8,8)

B(10,6)

C(2,2)

Answer: Reflecting over y = -1:

If a point is reflected over a y line, the x values remain the same while the y values change.

For point A(8, 8): The y distance between the y = - 1 line and point A is 9 units. (8- (-1)). If point A is reflected, the y value would be 9 units below the y = -1 line, i.e the new y coordinate would be at -10 (-1-9)

The new coordinate is at A'(8, -10)

For point B(10, 6): The y distance between the y = - 1 line and point B is 7 units. (6- (-1)). If point B is reflected, the y value would be 7 units below the y = -1 line, i.e the new y coordinate would be at -8 (-1-7)

The new coordinate is at B'(10, -8)

For point C(2, 2): The y distance between the y = - 1 line and point C is 3 units. (2- (-1)). If point C is reflected, the y value would be 3 units below the y = -1 line, i.e the new y coordinate would be at -4 (-1-3)

The new coordinate is at C'(2, -4)

Reflecting over y = -7 line:

For point A'(8, -10): The y distance between the y = - 7 line and point A' is 3 units. (-7- (-10)). If point A' is reflected, the y value would be 3 units above the y = -7 line, i.e the new y coordinate would be at -4 (-7+3)

The new coordinate is at A''(8, -4)

For point B'(10, -8): The y distance between the y = - 7 line and point B' is 1 units. (-7- (-8)). If point B' is reflected, the y value would be 1 units above the y = -7 line, i.e the new y coordinate would be at -6 (-7 + 1)

The new coordinate is at B'(10, -6)

For point C'(2, -4): The y distance between the y = - 7 line and point C' is 3 units. (-4- (-7)). If point C' is reflected, the y value would be 3 units below the y = -7 line, i.e the new y coordinate would be at -10 (-7-3)

The new coordinate is at C''(2, -10)

We can also see that h= −7−(−1)=−6. We know that two reflections is the same as a translation of 2h  units down. So 2(−6) is a translation of −12 units down.

5 0
3 years ago
Find the product and sum of the roots of the equation: 3x^2-10=0
cluponka [151]

● 3x^2 - 10 = 0

Add 10 to both sides

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Divide both sides by 3

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● √(10/3) + (-√(10/3)) = 0

● √(10/3) × -√(10/3) = -10/3

3 0
3 years ago
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