Hey who ever can help me, I give 25 points

System by substitution.<br> Tar 7x - 3y=8<br> y=3x

valentina_108 [34]

Answer:

3k

Step-by-step explanation:

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8 0

2 years ago

The conditional relative frequency table below was generated by column using frequency table data comparing the number of calori

inessss [21]

Answer:

B. There is an association because the value 0.15 is not similar to the value 0.55

Step-by-step explanation:

Based on the above picture, for the nutritionist to determine whether there is an association between where food is prepared and the number of calories the food contains, there must be an association between two categorical variables.

The conditions that satisfy whether there exists an association between conditional relative frequencies are:

1. When there is a bigger difference in the conditional relative frequencies, the stronger the association between the variables.

2. When the conditional relative frequencies are nearly equal for all categories, there may be no association between the variables.

For the given conditional relative frequency, we can see that there exists a significant difference between the columns of the table in the picture because 0.15 is significantly different from 0.55 and 0.85 is significantly different from 0.45

We can conclude that there is an association because the value 0.15 is not similar to the value 0.55

3 0

3 years ago

Read 2 more answers

Find the quadratic function y=f(x) whose graph has a vertex (−3,4) and passes through the point (−7,0). Write the function

olganol [36]

Answer:

Step-by-step explanation:

This is a parabola since a quadratic is a parabola. The standard form for a parabola is y = ax² + bx + c

but before we do that, we will use the vertex form, since it will make our work easier at the beginning.

First and foremost, when we plot the vertex and the given point, the vertex is higher up than is the point; that means that this parabola opens upside down, and its vertex form will be

y=-|a|(x - h)² + k

The absolute value is out in front of the a, so we know that the value of a is positive, but the quadratic itself is negative (upside down) and we will find that math takes care of that negative that needs to be out front. So we need to solve for a by filling in the x, y, h, and k values from the point and the vertex: x = -7, y = 0, h = -3, k = 4

0 = a(-7 - (-3))² + 4 and

0 = a(-7 + 3)² + 4 and

0 = a(-4)² + 4 and

0 = a(16) + 4 and

0 = 16a + 4 and

-4 = 16a so

$a=-\frac{1}{4}$

Now that we know a, we can plug it back into the vertex form and then put it into standard form from there.

$y=-\frac{1}{4}(x+3)^2+4$

Now we will FOIL out what's inside the parenthesis to get

$y=-\frac{1}{4}(x^2+6x+9)+4$

Simplify by distributing the -1/4 into the parenthesis:

$y=-\frac{1}{4}x^2-\frac{3}{2}x-\frac{9}{4}+4$

Combine like terms to get

$y=-\frac{1}{4}x^2-\frac{3}{2}x+\frac{7}{4}$

And there you go!

5 0

2 years ago

A website manager has noticed that during the evening hours, about 5 people per minute check out from their shopping cart and m

Over [174]

Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is made

c) 0.05% probability that seven people make a purchase in the next four minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that $\mu = 5$

a) What model might you suggest to model the number of purchases per minute? 

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per minute.

b) What is the probability that in any one minute at least one purchase is made? 

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want to find $P(X \geq 1)$

So

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067$

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is made

c) What is the probability that seven people make a purchase in the next four minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

$\mu = 4*5 = 20$

We have to find P(X = 7).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005$

0.05% probability that seven people make a purchase in the next four minutes

8 0

3 years ago

Enter the values for the highlighted variables that show how to subtract the rational expressions correctly:

LenKa [72]

Answer:

a = 6

x^2 + 6x is equal to x(x+6)

b=2

Denominator and numerator of the first term are multiplied by x.

c=6

Second term is multiplied by (x-6)/(x-6)

d=2

Now that they have the same denominator, the two terms are combined. 2 is the coefficient of the first term

e=6

In the same way as d is carried over from b, e is carried over from c.

f = 6

2x - x + 6 = x + 6

g = 1

We factor out the (x+6) from the numerator and denominator

6 0

2 years ago