Answer:
0.92 and 1.25 respectively
Step-by-step explanation:
0.92 and 1.25 respectively
first the mean of each value which is 9.7 and 9.8 respectively
standard deviation = square root of the mean deviation of each value
then deduct the mean from each element
and square each value and add them together. not you should square each deviation value before you add them
at last divide the result by the number of frequency and find it's square root
By the Pythagorean theorem,
.. x^2 +(x -46)^2 = (x +4)^2
.. 2x^2 -92x +2116 = x^2 +8x +16
.. x^2 -100x +2100 = 0
.. (x -50)^2 -400 = 0
.. x = 50 ±20 . . . . . only x=70 makes any sense in the problem
The height, x, of the tree is 70 meters.
Answer:
- The angle ∠2 = 4x = 4(36°) = 144°
Step-by-step explanation:
We know that when two lines meet or intersect, we get a linear pair of angles.
Linear pairs are basically two adjacent angles that form a line.
The measure of two adjacent angles forming a straight line is 180, meaning they are supplementary.
We are given that <1 and <2 forms a linear pair, and
m∠1 = 4m∠2
It means the angle ∠1 is 4 times the measure of angle ∠2.
Let the angle ∠1 be = x
As the angle 1 is 4 times the measure of angle ∠2, so
The angle 2 will be = 4x
As <1 and <2 forms a linear pair, thus the measure of the sum of <1 and <2 will be 180°, so
x + 4x = 180
5x = 180
divide both sides by 5
5x/5 = 180/5
x = 36°
Therefore,
- The angle ∠2 = 4x = 4(36°) = 144°
<span>Using place value to exchange equal amounts when renaming a number is called : Regroup
Simple example for a group is when you try to add up :
86 + 25
86 has 8 group of tens and 6 groups of one
25 has 2 groups of tens and 5 groups of one
after adding that up , now the number has 11 group of tens and 1 group of one, the result of that equation would be : 110</span>
The question ask on which of the following in you choices is the equation that best compares the slops of the two function and the best answer would be letter D. Slope of function B = - Slope of Function A, I hope you are satisfied with my asnwer and feel free to ask for more