150 more male bats need to be tagged
if you want 2/5 to be female you divide the 260 (<160+100) by 2 to get 130
then you multiply 130 by 3 to get the total amount of male bats that need to be tagged
130*3=390
then you subtract 240 from the 390 to find out how many more bats need to be tagged
390-240=150
M^3 + 9m =
There is a common factor of m.
= m(m^2 + 9)
That is the complete factorization.
m^2 + 9 is a sum of two squares which is not factorable.
Answer: m(m^2 + 9)
Answer AND Step-by-step explanation:
Everything is in the picture.
<em><u>#teamtrees #PAW (Plant And Water)</u></em>
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I highly recommend you use photomath for this. but i have the answer!
26-16x is the answer