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3 years ago

What is the value of x in the equation 15(x + 4) - 3 = 4.5(x - 2)?

Mathematics

1 answer:

IRISSAK [1]3 years ago

6 0

Hi there!

The Eqn. is :-

1.5 (x + 4) - 3 = 4.5 (x - 2)

1.5x + 6 - 3 = 4.5x - 9

Combining the like terms :-

1.5x - 4.5x = - 9 - 6 + 3

- 3x = - 15 + 3

- 3x = - 12

x = \dfrac {- 12}{- 3}

x = 4

Hence, the required answer is → x = 4

~ Hope it helps!

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please help me- this along with the last one and many more are worth a project grade and i need to pass school- quq

Alex

Each person would get $\frac{5}{8}$ pizza.

Solution:

Total quantity of pizza = $1\frac{7}{8}$

Number of persons shared = 3

To find how much pizza would each person get:

Let us first convert improper fraction into mixed fraction.

$$1\frac{7}{8}=\frac{1\times8 + 7}{8}=\frac{15}{8}$

Now divide the total quantity of pizza by the number persons shared.

$$\text{Quantity of pizza each person get}=\frac{(\frac{15}{8}) }{3}$

$$=\frac{15}{8\times3}$

$$=\frac{15}{24}$

Divide both numerator and denominator by 3.

$$=\frac{15\div3}{24\div3}$

$$=\frac{5}{8}$

Quantity of pizza each person get = $\frac{5}{8}$

Hence each person would get $\frac{5}{8}$ pizza.

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3 years ago

Solve the proportion 18/2 = t/7

Firlakuza [10]

Answer:

t=63

Step-by-step explanation:

2t = 126

t=63

3 0

2 years ago

Read 2 more answers

Please Elijah and Aubrey have summer jobs Elijah deposits the same amount of money in his account every week the equation is y =

Anika [276]

Answer:

Part a) $y=125x+23$

Part b) The graph of the equation for Aubrey's balance is parallel to the graph of Elijah's balance

Part c) Parallel graphs mean that their slopes are the same and that they deposited the same amount of $125 per week into their account balance during the summer.

Step-by-step explanation:

The correct question is

Elijah and Aubrey have summer jobs. Elijah deposits the same

amount of money in his account every week. The equation y = 125x + 72 represents his bank balance any given week of the summer. Aubrey also deposits the same amount into her account every week. At the end of the third week she has $398. At the end of the sixth week she has $773.

a. Write an equation to represent Aubrey's bank balance any given week of the summer.

b. Would the graph of the equation for Aubrey's balance be parallel to the graph of Elijah's balance? Explain.

c. What do the parallel graphs mean in terms of the situation?

Part a)

Let

x ----> the number of weeks

y ----> represent bank's balance

we know that

Elijah

$y=125x+72$ -----> equation A

Aubrey

we have the points

(3,398) and (6,773)

Find the slope m

$m=(773-398)/(6-3)$

$m=375/3$

$m=125$

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=125$

$point\ (3,398)$

substitute

$y-398=125(x-3)$ ----> equation in point slope form

Convert to slope intercept form

$y=mx+b$

$y-398=125x-375$

$y=125x-375+398$

$y=125x+23$ ----> Aubrey's bank balance

Part b)

Compare the equations

$y=125x+72$ ----> Elija's bank balance

$y=125x+23$ ----> Aubrey's bank balance

Remember that

If two lines are parallel, then their slopes are equal

In this problem the slopes are equal

$m=125\frac{\$}{week}$

therefore

The graph of the equation for Aubrey's balance is parallel to the graph of Elijah's balance

Part c) Parallel graphs mean that their slopes are the same and that they deposited the same amount of $125 per week into their account balance during the summer.

5 0

3 years ago

Solve the quadratic equation x square + 6 x + 9 equals 0

Nataly [62]

X^2 + 6x +9
(x+3) (x+3)

x+3 = 0
x = -3

answer: x=-3

4 0

3 years ago

Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1

denis23 [38]

Given that the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

$P(a\ \textless \ X\ \textless \ b)=P\left(z\ \textless \ \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\ \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \ \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \ \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\ \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344$

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4 years ago