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4 years ago

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Mathematics

1 answer:

AVprozaik [17]4 years ago

6 0

I hope this helps you

You might be interested in

Can someone answer these??

hoa [83]

Use the substitution method

Answers :

g(x)= -3x+1

a. g(10)= -3(10)+1

Mutiply first = -30

-30+1= -29

g(10)= -29

b. g(-2)= -3(-2)+1

Negative sign and negative sign = positive sign

-3(-2)= 6

6+1= 7

g(-2)= 7

f(x)=x^2+7

f(3)= 3^ 2+7

3*3 because of the exponent. 3*3= 9

9+7= 16

f(3)= 16

f(a)= a^2+7

a*a= a^2

a^2+7

f(a)= a^2+7

7 0

3 years ago

Pls explain me i will make u as brainlist

Mashutka [201]

Answer:

hope this help you

have a great day

4 0

3 years ago

What is the answer 1/2d > -3; d = 0

Valentin [98]

Answer:

0 is a solution for the given equation.

Step-by-step explanation:

$\frac{1}{2}d>-3\\\frac{1}{2}(0)>-3\\0>-3\\True$

8 0

3 years ago

Read 2 more answers

Select the correct domain and range of the relation. (-4, -4)(-1,3)(0,5)(3,9)

DaniilM [7]

Answer:

Domain: {1, 2, 3, 4}

Range: {3, 6, 9, 12}

Step-by-step explanation:

6 0

3 years ago

Find the equation of a line that passes through the points (1,-5) and (3,-6).

sdas [7]

Answer:

y = - $\frac{1}{2}$ x - $\frac{9}{2}$

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (1, - 5) and (x₂, y₂ ) = (3, - 6)

m = $\frac{-6+5}{3=2}$ = - $\frac{1}{2}$ , then

y = - $\frac{1}{2}$ x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (1, - 5 ) , then

- 5 = - $\frac{1}{2}$ + c ⇒ c = - 5 + $\frac{1}{2}$ = - $\frac{9}{2}$

y = - $\frac{1}{2}$ x - $\frac{9}{2}$ ← equation of line

7 0

3 years ago