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2 years ago

Find the slope of the line passing

Mathematics

1 answer:

Lana71 [14]2 years ago

4 0

The slope of the line formula: $\frac{y_2 - y_1}{x_2 - x_1}$

Next, you would have to plug in the coordinates.
$\frac{6 - 2}{9 + 7}$

Now, all you would have to do is solve and simplify it.
$\frac{6 - 2}{9 + 7}$ = $\frac{4}{16}$ = $\frac{1}{4}$

The slope would be $\frac{1}{4}$ .

I hope this helps!

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Can some one help!! big ponits

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Answer:

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Step-by-step explanation:

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A coin is to be tossed as many times as necessary to turn up one head. Thus the elements c of the sample space C are H, TH, TTH,

slavikrds [6]

Answer:

Step-by-step explanation:

As stated in the question, the probability to toss a coin and turn up heads in the first try is $\frac{1}{2}$ , in the second is $\frac{1}{4}$ , in the third is $\frac{1}{8}$ and so on. Then, P(C) is given by the next sum:

$P(C)=\sum^{\infty}_{n=1}(\frac{1}{2} )^{n}=1$

This is a geometric series with factor $\frac{1}{2}$ . Then is convergent to $\frac{1}{1-\frac{1}{2}}-1=1.$ . With this we have proved that P(C)=1.

Now, observe that

$P(H)=\frac{1}{2}, P(TH)=\frac{1}{4},P(TTH)=\frac{1}{8},P(TTTH)=\frac{1}{16},P(TTTTH)=\frac{1}{32},P(TTTTTH)=\frac{1}{64}.$

Then

$P(C1)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} =\frac{31}{32}$

$P(C2)=P(TTTTH)+P(TTTTTH)=\frac{1}{32}+\frac{1}{64} =\frac{3}{64}$

$P(C1\cap C2)=P(TTTTH)=\frac{1}{32}$

and

$P(C1\cup C2)=P(H)+P(TH)+P(TTH)+P(TTTH)+P(TTTTH)+P(TTTTTH)=\frac{1}{2} +\frac{1}{4} +\frac{1}{8} +\frac{1}{16} +\frac{1}{32} +\frac{1}{64}=\frac{63}{64}$

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2 years ago

karen wants to find the area of the isosceles triangle ABC. she knows that the base of the triangle (side CB) is equal to 8 squa

S_A_V [24]

Answer:

16 squares

Step-by-step explanation:

The area of an isosceles is $\frac{bh}{2}$

$8 \cdot 4 = 32\\32 \div 2 = 16$

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At the grocery store, apples are one price and chocolate bars are another. mary buys three apples and one chocolate bar for $2.7

mafiozo [28]

Answer:

Step-by-step explanation:

Step 1 is to collect the information in a table format. The attached Table1 summarizes what we know in columns 1 - 3. Columns 4 - 6 show the data we're about to calculate, so ignore them for the moment.

.I use A for the price of one apple and C for the price of 1 chocolate bar. We know how many of each are purchased by both Mary and Bill, and the total each paid.

The last column (6) shows the price for each, which comes from the derivation presented below.

We can set the information in columns 1 - 3 into equations:

Mary: 3A+1C = 2.70 [This states that Mary bought 3 apples at a price of A for each apple, and 1 chocolate bar at a price of C per bar.]

Bill: 1A + 4C = 6.40 [In the same fashion, this summarizes how Bill parted with his $6.40]

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Now let's rearrange either equation to solve for C. I'll use Mary's equation:

3A+1C = 2.70

1C = 2.70 - 3A

This tells us that the price of 1 chocolate bar is $2.70 minus the cost of 3 apples. Interesting, but we need the price of a chocolate bar to determine an exact amount.

----

Now take Bill's equation and substitute the value we just derived for the price of a chocolate bar <u>C</u> = (2.70-3A).

1A + 4<u>C</u> = 6.40

1A + 4(2.70 - 3A) = 6.40

1A + 10.80 - 12A = 6.40

-11A = -4.40

A = 0.40 This is the price for 1 apple. This is the value in the last column (6) of attached Table1.

---

Now we can use the value of $0.40 in either equation to find the price of a chocolate bar. I'll use the rearranged equation we developed for Mary:

1C = 2.70 - 3A

1C = 2.70 - 3(0.40) [A = 0.40 from the above work]

1C = 2.70 - 1.20

1C = 1.50

The price of 1 chocolate bar is $1.50. Pricey, and bad for health. But very tasty.

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AnnyKZ [126]

Answer:

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Step-by-step explanation:

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