Answer:
It is the user tier of the 3-tier architecture that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.
Explanation:
Almost if not all applications that use e-commerce for operations use the 3-tier architecture. 3-tier architecture is simply the arrangement of server tier which consists of all computers that run a web server and a database tier that consists of computers that run a DBMS to store and retrieve data. We also have the user data that consists of computers, phones, and other mobile devices that have browsers that request and process web pages.
When you make a request, for instance to Google in your local browser, the browser sends a request to the internet. This initial interaction between the user and the internet is what is known as the user tier of the 3 tier architecture. Basically, it is the phase where end users access content online through graphical interface browsers and make requests to the web servers and DBMS.
Learn more about 3-tier architecture
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Answer:
Semaphores carries the signal between the task and interrupts that does not carry any type of additional data in the embedded system. A semaphore is used as synchronization object and helps in maintain the value between zero and the specific higher value.
It basically reduced the value each time and complete the semaphore object in the embedded system. Binary semaphores is the main type of semaphore that invoke activation of the task.
<span>Hey there, this isn't really my part of town, I'm what you call a math freak, but here.
In relation to computer processors, a core
is the processing kinda like a brain we ppl have, this is the unit that receives instructions and performs
calculations, or actions, based on those instructions like when you click something. A set of
instructions can allow a software program perform a specific function.
Processors can have a single core or multiple cores that do many different things.
Hopefully i helped you, please mark brainly if possible.</span><span />
Answer:
a) 
b) 
c) 10000 programs.
Explanation:
a) We know that the frequency is the inverse of the period, so:

1μs is equal to 
so 
b) If in a second there are 2.5*10^9 cycles:

c) we have to make a conversion, we know that a program takes 100*10^(-3) milliseconds, that is, 1*10^(-4) seconds so in 1 second we can execute:

10000 programs.