Answer:
here ya go
Explanation:
A computer is a powerful tool because it is able to perform the information processing cycle operations (input, process, output, and storage) with amazing speed, reliability, and accuracy; store huge amounts of data and information; and communicate with other computers.
Answer:
for i in range(200,301,2):
print(i)
Explanation:
just copy and paste 100 percent
Answer: A
Explain:
you can use memory on a computer to retrieve passed data if your referring to brains memory that is memory of passed events
memory:1 the faculity by which the mind stores and members information
2 something remembered from the past a recollection
The program is an illustration of built-in functions
<h3>What are
built-in functions?</h3>
They are named program statements that have a predefined purpose
<h3>The actual program</h3>
The program written in C++, where comments are used where required is as follows:
#include <iostream>
#include <cmath>
#include <ios>
#include <iomanip>
using namespace std;
int main (){
double x;
double y;
double z;
cin>>x;
cin>>y;
//This calculates the given expression
z = pow(sqrt(y),x);
cout << fixed<<setprecision(2);
cout<<z<<endl;
return 0;
}
Read more about python functions at:
brainly.com/question/14284563
Options :
A.) s1 < s2
B.) s1 <= s2
C.) s1.compareTo(s2) == −1
D.) s2.compareTo(s1) < 0
E.) s1.compareTo(s2) < 0
Answer: E.) s1.compareTo(s2) < 0
Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.
If first string = s1 ; second string = s2
To compare s1 with s2, the format is ;
s1.compareTo(s2) ;
If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.
If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.
If both are s1 and s2 are the same, the output will be 0.
