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kow [346]
4 years ago
5

Help anyone please!!!!!!

Mathematics
1 answer:
Alla [95]4 years ago
5 0

Answer:

Step-by-step explanation:

The quotient, found using long division, is x + 2, and the remainder is 4.

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Y=2x+5 and y=3x+11 solve by substitution.
kondaur [170]

Answer:

Answer: x= -6 and y= -7

Step-by-step explanation:

Substitute 2x+5 for y in y=3x+11:

y=3x+11

2x+5=3x+11

2x+5+−3x=3x+11+−3x(Add -3x to both sides)

−x+5=11

−x+5+−5=11+−5(Add -5 to both sides)

−x=6

−x−1=6−1(Divide both sides by -1)

x=−6

Step: Substitute −6 for x in y=2x+5:

y=2x+5

y=(2)(−6)+5

y=−7(Simplify both sides of the equation)

-Source: MathPapa

6 0
3 years ago
What is larger <br> a. 3.2x10^5<br> b.4.2x10^3<br> c. 1.1x10^5
Nataliya [291]
The answer is a. 3.2x10^5  hope this helps!
3 0
4 years ago
Read 2 more answers
Plzzzzzz help!!! NO LINKS OR FILES PLZZ
tensa zangetsu [6.8K]

Answer: A

Step-by-step explanation: Hope this help :D

3 0
3 years ago
The probability distribution of a random variable X is given. x 1 2 3 4 P(X = x) 0.4 0.1 0.3 0.2 Compute the mean, variance, and
Readme [11.4K]

Mean:

E(X) = \displaystyle \sum_{x\in\{1,2,3,4\}}x\,P(X=x) = 1\times0.4 + 2\times0.1 + 3\times0.3 + 4\times0.2 = \boxed{2.3}

Variance:

\displaystyle V(X) = E\left((X-E(X))^2\right) = E(X^2) - E(X)^2 \\\\ E(X^2) = \sum_{x\in\{1,2,3,4\}}x^2\,P(X=x) = 1^2\times0.4 + 2^2\times0.1 + 3^2\times0.3 + 4^2\times0.2 = 6.7 \\\\ \implies V(X) = 6.7 - 2.3^2 = \boxed{1.41}

Standard deviation:

\sigma_X = \sqrt{V(X)} = \sqrt{1.41} \approx \boxed{1.19}

5 0
3 years ago
The length of the hypotenuse line segment AC in right triangle ABC is 25 cm. The length of line segment BC is 15 centimeters. Wh
Elden [556K]

From my understanding you ahould use the trig function cos to solve this.
cos(c) = 15/25 or 0.6
if you have this following function on your calculator I suggest using it:

cos ^{ - 1}

by using the function like so:

cos^{ - 1} (0.6

you should get about 53.13° (rounding to the nearest hundredth)
Hope this helped.
8 0
3 years ago
Read 2 more answers
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