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3 years ago

Can anyone help me with this math problem? Thank you.

Mathematics

1 answer:

pickupchik [31]3 years ago

4 0

Step-by-step explanation:

Answer is in the picture.

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Determine the resulting polynomial: <br> f(x)=10x−5<br> g(x)=2x2+4x−4<br> Find: f(x)⋅g(x)

Lina20 [59]

40x^2 - 20x

(10x-5)(2*2+4x-4)
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40x^2 - 20x

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3 years ago

. Look at each equation and possible solution. Is the solution correct? Select Yes or No for

insens350 [35]

A. No B. No C. Yes I honestly don’t know if that’s 100% right tho

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3 years ago

Write 2/9<br> as a recurring decimal

Stolb23 [73]

Answer:

0.2222222...

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

I need help asap D:

Airida [17]

Answer:

Step-by-step explanation:

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2 years ago

Scientists were studying a rare species of parrot. They went to a forest in the year

Brrunno [24]

Answer:

$P(t) = 608(1.5)^{t}$

Step-by-step explanation:

The number of parrots in t years after 2010 can be modeled by the following function:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the number of parrots in 2010 and r is the growth rate, as a decimal.

608 parrots in the forest in 2010.

This means that $P(0) = 608$

Then

$P(t) = 608(1+r)^{t}$

When the scientists went back 5 years later, they found 4617 parrots.

This means that $P(5) = 4617$

We use this to find 1 + r. So

$P(t) = 608(1+r)^{t}$

$4617 = 608(1+r)^{5}$

$(1+r)^{5} = \frac{4617}{608}$

$1 + r = \sqrt[5]{\frac{4617}{608}}$

$1 + r = 1.5$

$P(t) = 608(1.5)^{t}$

8 0

3 years ago