25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
a = 3
Step-by-step explanation:
1) Simplify 5a - 9 + a to 6a - 9.
2) Add 9 to both sides.
3) Simplify 9 + 9 to 18.
4) Divide both sides by 6.
5) Simplify 18/6 to 3.
Therefor, the answer is, a = 3.
Answer:
The answer is: y = - |x+1|+1
I do not have an answer for that, but you should try looking for that on google or yahoo answers.
Answer:
multiply the original coordinate by 3 so its c
Step-by-step explanation:
multiply the original coordinate by 3
