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DIA [1.3K]
3 years ago
5

What is the next term in the sequence 58, 47, 36, 25, ...? –58 –8 14 69

Mathematics
2 answers:
ankoles [38]3 years ago
7 0

Answer:

Option C. 14

Step-by-step explanation:

Given sequence is 58, 47, 36, 25.....

We have to find the next term of this sequence.

Firstly we have to check whether sequence is arithmetic or geometric.

For Arithmetic sequence....

Common difference = 47 - 58 = (-11)

                                  = 36 - 47 = (-11)

                                  = 25 - 36 = (-11)

Common difference is (-11) for every succeeding term, so sequence is an arithmetic sequence.

For geometric sequence

common ratio = 47÷58 ≠ 36÷47 ≠ 25÷36

So ratio is not equal which clearly tells that this sequence is not a geometric sequence.

Now next term of the arithmetic sequence will be given by the explicit formula T_{n}=a + (n-1)d

For 5th term will be

T(5) = 58 + (5 - 1)(-11) = 58 + (-11)4 = 58 - 44 = 14

Option C. 14 is the answer.

34kurt3 years ago
4 0
The answer is 14 
I hope this helps!
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3 years ago
Godfrey plays a game in which he throws two fair six sided dice. If he rolls two sizes, he wins 20p, if he rolls one six, he win
blagie [28]

Answer:

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Step-by-step explanation:

If random variable X represents the amount Godfrey gains in one turn.

There are 3 different possible outcomes for X.

- Godfrey pays 5p to enter the game and gets two sixes and wins 20p.

Net gain = 15p

Probability of getting two sixes from two fair dice

= (number of outcomes with two sixes) ÷ (total number of outcomes)

number of outcomes with two sixes = 1

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (1/36) = 0.0278

- Godfrey pays 5p to enter the game and gets only one six and wins 10p.

Net gain = 5p

Probability of getting one six from either of two fair dice

= (number of outcomes with one six) ÷ (total number of outcomes)

number of outcomes with one six = 2 × n[(6,1), (6,2), (6,3), (6,4), (6,5)] = 2 × 5 = 10

total number of possible outcomes = 36

Probability of getting two sides from two fair dice = (10/36) = 0.278

- Godfrey pays 5p to enter the game and doesn't win anything

Net gain = -5p

Probability of not getting two sixes or one six.

= 1 - [(Probability of getting two sixes) + (Probability of getting one six on.wither dice)]

= 1 - 0.0278 - 0.278 = 0.6942

Probability of getting not getting two sixes or one six = 0.6942

The Probabilty distribution for the amount Godfrey gains in one turn is then given as

X ||| P(X)

15p | 0.0278

5p | 0.278

-5p | 0.6942

Hope this Helps!!!

4 0
4 years ago
Read 2 more answers
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krek1111 [17]

Answer:

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Step-by-step explanation:

Turn this into an equation: first, take the amount of hamburgers and call it 3x due to it being 3 times more than the amount of cheeseburgers, which we will can call x.

So, X+3X=444 is what you need to solve this. This is the same as 4x=444

So, x=111

Now, Input 111 for the final answer; 333 cheeseburgers and 111 hamburgers

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