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sladkih [1.3K]
3 years ago
5

Corey has 16 cups of flour to make cookies. one batch of cookies takes 2.5 cups of flour. if he must save 6 cups of flour for ot

her baking, write and solve and solve an inequality to determine how many batches of cookies he can make. Interpret the solution.

Mathematics
1 answer:
babunello [35]3 years ago
8 0
Since 1 batch is 2.5 cups and he needs to save 6.. what you'll do is subtract 16-6. The. You create a proportion.. You cross multiply then divide..

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Please help
Ann [662]

Answer:

1/60 probabiliity

Step-by-step explanation:

You have two independent events that you want to put together.

Let Pr. mean "probability"

Pr(5 from 10 cards and 2 on a dice ) = Pr(5 from 10 cards) * Pr( 2 on a dice)

Pr(5 from 10 cards and 2 on a dice ) =(1/10) * (1/6)

= 1/60

Pr(5 from 10 cards and 2 on a dice ) =0.0167

or 1.67% probability

5 0
3 years ago
List the subsets of the set { dog,cat,rabbit}
ser-zykov [4K]

Answer: so dog goes to cat, dog goes to rabbit and cat goes to rabbit I think

Step-by-step explanation:

7 0
3 years ago
Complete the square to rewrite x^2+y^2+2x+6y-6=0 in graphing form
Ksivusya [100]

Answer:

(x + 1)² + (y + 3)² = 16

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

Given

x² + y² + 2x + 6y - 6 = 0

Collect the x and y terms together and add 6 to both sides

x² + 2x + y² + 6y = 6

To complete the square

add ( half the coefficient of the x/ y terms )² to both sides

x² + 2(1)x + 1 + y² + 2(3)y + 9 = 6 + 1 + 9

(x + 1)² + (y + 3)² = 16

with centre = (- 1, - 3) and r = \sqrt{16} = 4

4 0
3 years ago
What is the area of this shape?
Andre45 [30]
The answer is 104ft ( Ask for work if you need to)
3 0
3 years ago
Suppose n(x)= 22 and n(y) is 13 what is the maximum number of elements X ∪Y can have ?
Nikolay [14]
The inclusion/exclusion principle states that

|X\cup Y|=|X|+|Y|-|X\cap Y|

That is, the union has as many members as the sum of the number of members of the individual sets, minus the number of elements contained in both sets (to avoid double-counting).

Therefore, |X\cup Y| will have the most elements when the sets X and Y are disjoint, i.e. X\cap Y=\emptyset, which would mean the most we can can in this case would be

|X\cup Y|=|X|+|Y|=22+13=35

(Note that n(X)=|X| denotes the cardinality of the set X.)
3 0
4 years ago
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