Answer:
Aluminium.
Explanation:
The above electronic configuration can be written in a simplified form as shown below:
1s² 2s²2p⁶ 3s²3p¹
Next, we shall determine the number of electrons in the atom of the element as follow:
Number electron = 2 + 2 + 6 + 2 + 1
Number of electron = 13
Next, we shall determine the number of protons.
Since the element is in its neutral state,
The number of electrons and protons are equal i.e
Proton = Electron
Number of electron = 13
Proton = Electron = 13
Proton = 13
Next, we shall determine the atomic number of the element.
The atomic number of an element is simply the number of protons in the atom of the element i.e
Atomic number = proton number
Proton = 13
Atomic number = 13
Comparing the atomic number of the element with those in the periodic table, the element with the above electronic configuration is aluminium since no two elements have the same atomic number.
Molality of C2H5OH is 1.1.27m.
What is Molality?
Molality is no.of moles present in One Kg solution .
Molality is represented by m
m= no.of moles/ weigt of solution in kg
Given is Molarity= 51.30M
molar mass of C2H5OH is 46g / mol , Density =0.9349g/ ml
Density=m/V
V = 107 ml
Molarity= no of moles/ Volume
51.5×46×107= x × 1000
weight of C2H5OH = 27.7g
molality = 27.7/1000××46
m= 1.27m
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Answer:
The molar concentration of radon is 4.38 x 10⁻⁶ mol.L⁻¹
Explanation:
Molar fraction = number of moles of a certain component / total number of moles
Partial pressure = Total pressure x molar fraction
Partial pressure = 34 atm x 3.2 x 10⁻⁶
Partial pressure = 1.09 x 10⁻⁴ atm
Considering radon as an ideal gas, PV = nRT
molar concentration = n/V
n/V = P/RT
n/V = 1.09 x 10⁻⁴ atm / 0.082 L.atm.mol⁻¹K⁻¹ x 303.15K
n/V = 4.38 x 10⁻⁶ mol.L⁻¹