Answer:
Increasing the temperature
Explanation:
According to Le Chatelier's principle, "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".
Since the forward reaction is exothermic, this suggests that heat is given off in the reaction.
Increasing the temperature will favors the reverse process which is endothermic.
In going from the reactants to the the products, the reaction is deemed exothermic which suggests that it produces heat.
The backward reaction is endothermic i.e it absorbs heat. If the temperature is increased, this process will be favored and more reactants produced. Less of the diiodine pentoxide will form. There is a leftward shift of the equilibrium
Dehydrogenation is catalyzed by Cu, Mo and Fe by changing their oxidation states.
It is a type of property which is normally not visible but when it undergoes certain chemical reactions then this property is visible
Balanced chemical reaction happening here is:
3Mg(s) + N₂(g) → Mg₃N₂(s)
<u>moles of product formed from each reactant:</u>
2.0 mol of N2 (g) x <u> 1 mol Mg₃N₂ </u> = <u>2 mol Mg₃N₂</u>
1 mol N2
and
8.0 mol of Mg(s) x <u> 1 mol Mg₃N₂ </u> = 2.67 mol Mg₃N₂
3 mol Mg
Since N2 is giving the least amount of product(Mg₃N₂) ie. 2 mol Mg₃N₂
N2 is the limiting reactant here and Mg is excess reactant.
Hence mole of product formed here is 2 mol Mg₃N₂
molar mass of Mg₃N₂
= 3 Mg + 2 N
= 101g/mol
mass of product(Mg₃N₂) formed
= moles x Molar mass
= 2 x 101
= 202g Mg₃N₂
<u>202g of product are formed from 2.0 mol of N2(g) and 8.0 mol of Mg(s).</u>
<u> </u> The following are indicators of chemical changes:
Change in Temperature
Change in Color
Formation of a Precipitate
