Well, from 2008 to 2010 is just 2 years, so let's say the initial amount is the 19300 from 2008, how many will it be in 2010?
Answer:
B.) 2(5x-4)(x+1)
Step-by-step explanation:
10x^2+2x-8
= 2(5x^2 + x - 4)
= 2(5x^2 + 5x - 4x - 4)
= 2[5x(x + 1) - 4(x + 1)]
= 2(5x-4)(x+1)
Then that would be 3 and 9.
Answer:
6
Step-by-step explanation:
To find the third term substitute n = 3 into the n th term formula
a(3) = 

= 

=
× 4 = 6
Answer:
2/3, 1,2,4
Step-by-step explanation: