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Mekhanik [1.2K]

3 years ago

11

Find x, if the perimeter is 106 3x+6 2x-3

1 answer:

slega [8]3 years ago

3 0

So we are given that the perimeter is 106 and two problems to solve
we will write this as an equation
106 = 3x + 6
we will subtract 6 from both sides
100 = 3x
now divide by 3 to isolate the variable
we will get 33 1/3 as the x

for the second one
106 = 2x - 3
add three to both sides
109 = 2x
divide by 2 to isolate the variable
we will get 54 1/2 as the x

Hope this helps :)

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Answer:

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Step-by-step explanation:

<u><em>The correct question is</em></u>

What is the sum of the roots of 20x^2-10x-30

we know that

In a quadratic equation of the form

$ax^{2} +bx+c=0$

The sum of the roots is equal to

$-\frac{b} {a}$

in this problem we have

$20x^{2} -10x-30=0$

so

$a=20\\b=-10\\c=-30$

substitute

$-\frac{(-10)} {20}=0.5$

<u><em>Verify</em></u>

Find the roots of the quadratic equation

The formula to solve a quadratic equation is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

$a=20\\b=-10\\c=-30$

substitute

$x=\frac{-(-10)\pm\sqrt{-10^{2}-4(20)(-30)}} {2(20)}$

$x=\frac{10\pm\sqrt{2,500}} {40}$

$x=\frac{10\pm50} {40}$

$x=\frac{10+50} {40}=1.5$

$x=\frac{10-50} {40}=-1$

The roots are x=-1 and x=1.5

The sum of the roots are

$-1+1.5=0.5$ ----> is ok

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