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brilliants [131]
4 years ago
12

Find the axis of symmetry for this parabola y=-5x^2-10x-15 write it as an equation

Mathematics
2 answers:
Ksju [112]4 years ago
6 0
Axis of symmetry is the x value of the vertex

the x value of the vertex, in form
y=ax^2+bx+c is -b/(2a)

so
y=-5x^2-10x-15
a=-5
b=-10

x value of vertex is -(-10)/(2*-5)=10/-10=-1
x=-1 is axis of symmetry
deff fn [24]4 years ago
3 0
X= -1
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