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tatiyna
1 year ago
5

The chance of getting a viral infection is 0.0005. out of 10,000 people, about how many of them are expected to get infected?

Mathematics
1 answer:
polet [3.4K]1 year ago
8 0

The computation shows that the number of people expected to get infected is 5.

<h3>How to calculate the value?</h3>

It should be noted that the chance of chance of getting a viral infection is 0.0005. out of 10,000 people.

Therefore, the number of people expected to get infected will be:

= 0.0005 × 10000

= 5

The number of people expected to get infected is 5.

Learn more about computations on:

brainly.com/question/4658834

#SPJ1

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The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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The lower limit of this interval is:

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The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.42 + 2.575\sqrt{\frac{0.42*0.58}{100}} = 0.547

The 99% confidence interval for the true population proportion of people with kids is (0.293, 0.547).

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