The chance of getting a viral infection is 0.0005. out of 10,000 people, about how many of them are expected to get infected?

Mathematics

1 answer:

polet [3.4K]1 year ago

8 0

The computation shows that the number of people expected to get infected is 5.

<h3>How to calculate the value?</h3>

It should be noted that the chance of chance of getting a viral infection is 0.0005. out of 10,000 people.

Therefore, the number of people expected to get infected will be:

= 0.0005 × 10000

= 5

The number of people expected to get infected is 5.

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Integrate [0, 1/2] xcos(pi*x).

elena-14-01-66 [18.8K]

To answer your question, this could be the possible answer and i hope you understand and interpret it correctly:
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let u=x so that du=dx
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v=(1/pi)sin(pi*x)
integration by parts
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3 0

3 years ago

Suppose the leader of a camping trip is putting together a trail mix

wel

Answer:

8 pounds of peanuts, 6 pounds of raisins and 6 pounds of chocolate chips

Step-by-step explanation:

Let x be the number of pounds of peanuts and y be the number of pounds of raisins and chocolate chips.

Peanuts cost $2 per pound, then x pounds cost $2x.

Raisins cost $2.50 per pound, then y pounds cost $2.50y.

Chocolate chips cost $4 per pound, then y pounds cost $4y.

In total, x+y+y=20 and those 20 pounds cost