a diamond ring was reduced from $799.99 to $499.99 find the percent decrease in the price round the answer to the nearest tenth
1 answer:
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Answer:
see attachment for graph
Step-by-step explanation:
< or > : dashed line
≤ or ≥ : solid line
< or ≤ : shade below the line
> or ≥ : shade above the line
<u>To graph the line y < 3x-2</u>
Rewrite the equation as: y = 3x - 2
Find two points on the line:
when x = 0, y = 3(0) - 2 = -2 → (0, -2)
when x = 3, y = 3(3) - 2 = 7 → (3, 7)
Plots the found points (0, -2) and (3, 7).
Draw a straight, dashed line through the points.
<u>To graph the line y ≥ -x + 3</u>
Rewrite the equation as: y = -x + 3
Find two points on the line:
when x = 0, y = -(0) + 3 = 3 → (0, 3)
when x = 3, y = -(3) + 3 = 0 → (3, 0)
Plots the found points (0, 3) and (3, 0).
Draw a straight, solid line through the points.
Shade above the solid line and below the dashed line to the right of where the two lines intersect. <u>The shaded area is the area of all possible solutions</u>.
a. The first part asks for how many ways they can be seated together in a row. Therefore we want the permutations of the set of 6 people, or 6 factorial,
6! = 6 5
= 30 4
= 360 2 = 720 possible ways to order 6 people in a row
b. There are two cases to consider here. If the doctor were to sit in the left - most seat, or the right - most seat. In either case there would be 5 people remaining, and hence 5! possible ways to arrange themselves.
5! = 5 4
= 20 3
= 120 1 = 120 possible ways to arrange themselves if the doctor were to sit in either the left - most or right - most seat.
In either case there are 120 ways, so 120 + 120 = Total of 240 arrangements among the 6 people if the doctor sits in the aisle seat ( leftmost or rightmost seat )
c. With each husband on the left, there are 3 people left, all women, that we have to consider here.
3! = 3 2 6 ways to arrange 3 couples in a row, the husband always to the left