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Dovator [93]
2 years ago
6

a diamond ring was reduced from $799.99 to $499.99 find the percent decrease in the price round the answer to the nearest tenth

of a percent if necessary​
Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
3 0

Answer:

The price was reduced by about 53%

Step-by-step explanation:

Per cent of change = (amount of change) ÷ (original amount)

% change = (799.99 - 375.99)/799.99

= 424 / 799

= .5300

= 53 %

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a summer camp has 250 campers. there are 32 more boy campers than girl campers. which system of equations represents the situati
g100num [7]
32 + x + x = 250
2x + 32 = 250
3 0
2 years ago
Read 2 more answers
Consider the following. f(x, y, z) = x2yz − xyz8, P(6, −1, 1), u = 0, 4 5 , − 3 5 (a) Find the gradient of f. ∇f(x, y, z) = (b)
Darina [25.2K]

Answer:

a)  ∇f(x, y, z) = (2xyz − yz⁸, x²z − xz⁸, x²y − 8xyz⁷)

b)  ∇f(6, −1, 1) = (-11, 30, 12)

c)  Duf(6, −1, 1) = 84/5

Step-by-step explanation:

Given

f(x, y, z) = x²yz − xyz⁸

P(6, −1, 1)

u = (0, 4/5, − 3/5)

a) ∇f(x, y, z) = ?

We apply

fx(x, y, z) = 2xyz − yz⁸

fy(x, y, z) = x²z − xz⁸

fz(x, y, z) = x²y − 8xyz⁷

then

∇f(x, y, z) = (2xyz − yz⁸, x²z − xz⁸, x²y − 8xyz⁷)

b) ∇f(6, −1, 1) = (2*6*(-1)*1 − (-1)(1)⁸, (6)²(1) − (6)(1)⁸, (6)²(-1) − 8(6)(-1)(1)⁷)

⇒  ∇f(6, −1, 1) = (-11, 30, 12)

c) Duf(6, −1, 1) = ∇f(6, −1, 1)*(0, 4/5, − 3/5) = (-11, 30, 12)*(0, 4/5, − 3/5)

⇒  Duf(6, −1, 1) = 0 + 24 - 36/5 = 84/5

5 0
3 years ago
Which figure has a greater volume and by how much?
sammy [17]

Answer:

15cm

but im not sure sorry

4 0
3 years ago
How should this model be completed to represent 605 ÷ 18?
rosijanka [135]

Answer:

Check the attached image

4 0
1 year ago
Four different sets of objects contain 2,5,6, and 7 objects, respectively. How many unique combinations can be formed by picking
Ilia_Sergeevich [38]
There are 2 choices for the first set, and 5 choices for the second set. Each of the 2 choices from the first set can be combined with each of the 5 choices from the second set. Therefore there are 2 times 5 combinations from the first and second sets. Continuing this reasoning, the total number of unique combinations of one object from each set is:
2\times5\times\times6\times7=420\ combinations
8 0
3 years ago
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