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3 years ago

What is the simplified expression for 6(2(y+x))?

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

Answer:

12x + 12y (Answer B)

Step-by-step explanation:

Multiply 6 and 2 together immediately, obtaining 12(x + y). This is the simplest form of the given expression. If you choose to multiply this out, you'll get

12x + 12y (Answer B)

koban [17]3 years ago

5 0

It should be B I know how to do it

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Step-by-step explanation:

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3 years ago

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Answer:

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3 years ago

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Simplify this expression 10b+7-3b-2

iren2701 [21]

Answer:

7b+5

Step-by-step explanation:

10b + 7 − 3b −2

=10b + 7 + −3b + −2

Combine Like Terms:

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3 years ago

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Mrs. Gomes found that 40% of students at her high school take chemistry. She randomly surveys 12 students. What is the probabili

zlopas [31]

Answer:

The correct answer to the following question will be "0.438".

Step-by-step explanation:

Just because Mrs. Gomes finds around 40% of students in herself high school are studying chemistry.

Although each student becomes independent of one another, we may conclude:

"x" number of the students taking chemistry seems to be binomial to p = constant probability = 0.40

Given:

Number of surveys

= 12

Exactly 4 students have taken chemistry:

$=P(X\leq4)$

$=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)$

$=\Sigma_{0}^{4} C_{r}(0.4)^r(0.6)^{12-r}$

On substituting the above equation, we get the probability of approximately "0.438".

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3 years ago

Find y'' by implicit differentiation. 4x^3 + 5y^3 = 4

iVinArrow [24]

$\bf 4x^3+5y^3=4\implies 12x^2+15y^2\cfrac{dy}{dx}=0\implies 4x^2+5y^2\cfrac{dy}{dx}=0
\\\\\\
5y^2\cfrac{dy}{dx}=-4x^2\implies \boxed{\cfrac{dy}{dx}=\cfrac{-4x^2}{5y^2}}\\\\
-------------------------------\\\\
\cfrac{d^2y}{dx^2}=\stackrel{quotient~rule}{\cfrac{-8x(5y^2)~~-~~(-4x^2)(10y)\left( \frac{dy}{dx} \right)}{(5y^2)^2}}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}$

$\bf \cfrac{d^2y}{dx^2}=\cfrac{-40xy^2+(40x^2y)\left( \frac{-4x^2}{5y^2} \right)}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^2-\frac{160x^4y}{5y^2}}{25y^4}\implies 
\cfrac{d^2y}{dx^2}=\cfrac{\frac{-200xy^4-160x^4y}{5y^2}}{25y^4}
\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-200xy^4-160x^4y}{(25y^4)(5y^2)}\implies 
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\\\\\\
\cfrac{d^2y}{dx^2}=\cfrac{-40xy^4-32x^4y}{25y^6}$

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3 years ago