Answer:What are the equivalence classes of the equivalence relations in Exercise 3? A binary relation defined on a set S is said to be equivalence relation if it is reflexive, symmetric and transitive. An equivalence relation defined on a set S, partition the set into disjoint equivalence classes
21 is the answer.You distribute 6 into the parentheses and you substitute 3 for x so 6(3-1)+9= f(x)=18-6+9 you add all the like terms and the answer is 21
The value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
<h3>Vertex Form of a quadratic expression</h3>
Given the quadratic expressions
1.5x^2+6x+......
1.5(x^2 + 4x)
Using the completing the square method
The coefficient of x = 4
Half of the coefficient = 4/2 = 2
The square of the result = 2^2 = 4
The equation is expressed as:
f(x) = 1.5(x^2+4x+ 4) - 4
f(x) = 1.5(x+2)^2 - 4
Hence the value of the expression in the form a(x+b)^2 is 1.5(x+2)^2 - 4
Learn more on completing the square method here: brainly.com/question/1596209
Answer:
0.6804
Step-by-step explanation:
Given that Margie is practicing for an upcoming tennis tournament. Her first serve is good 20 out of 30 times on average.
Since each trial is independent and there are two outcomes, X no of good serves is binomial with n=6 and p =2/3
Required probability
= Prob that atleast four of 6 times good serve
=
=
Formula used:
P(X=r) =
Answer:
First of all, he have to find out what 0.5% of the students is.
Second of all, find out what 0.5 of 100 is. 100 divided by 0.5 is 200.
Third of all, divide 200 from 639. This equals 3.195
Since it is asking about how many, I would go with about 3. After all, you can't have have half of a person, so the decimals shouldn't be added.
Step-by-step explanation: