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xeze [42]
3 years ago
7

Find the missing values in the ratio table then right the equivalent ratio

Mathematics
2 answers:
PtichkaEL [24]3 years ago
8 0
10/4= 2.5
5/2.5= 2
2 would be your first answer

32x2.5= 80
80 would be your second answer

Hope this helped
Klio2033 [76]3 years ago
5 0
Cat box=80
dog box= 2

Unit rate=cat to dog= 2.5 to 1
regualr ratio=cat to dog is 5 to 2

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One kind of hard candy sells for $.89 per kilogram another sells for $1.10 per kilogram how many kilograms of each kind a need t
Furkat [3]

Answer:

20kg of $0.89 candy

10kg of $1.10 candy

Step-by-step explanation:

Candy 1 = 0.89 per kg

Candy 2 = 1.10 per kg

Total kilogram, kg = 30

Let candy 1 = x ; candy 2 = (30 - x) ;

0.89x + 1.10(30 - x) = 0.96(30)

0.89x + 33 - 1.10x = 28.8

0.89x - 1.10x = 28.8 - 33

-0.21x = - 4.2

x = 4.2 / 0.21

x = 20

20kg of $0.89 candy

(30 - x) = (30 - 20) = 10kg

10kg of $1.10 candy

4 0
2 years ago
For the given term, find the binomial raised to the power , whose expansion it came from: 10a ^ 3 * b ^ 2 .
9966 [12]

Answer:

i dont know sorry

Step-by-step explanation:

7 0
3 years ago
Four cards are dealt from a standard fifty-two-card poker deck. What is the probability that all four are aces given that at lea
elena-s [515]

Answer:

The probability is 0.0052

Step-by-step explanation:

Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:

P(A/B) =  P(A∩B)/P(B)

The probability P(B) that at least three are aces is the sum of the following probabilities:

  • The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
  • There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

nCk=\frac{n!}{k!(n-k)!}

So, the number of ways to select exactly 3 aces is:

4C3*48C1=\frac{4!}{3!(4-3)!}*\frac{48!}{1!(48-1)!}=192

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725

Then, the probability P(B) that at least three are aces is:

P(B)=\frac{1}{270,725} +\frac{192}{270,725} =\frac{193}{270,725}

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:

P(A∩B) = 1/270,725

Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

P=\frac{1/270,725}{193/270,725} =\frac{1}{193}=0.0052

5 0
3 years ago
A family spends 1⁄10 of its annual income for housing, 1⁄4 for food and clothing, 1⁄5 for general expenses, and 2⁄15 for enterta
tankabanditka [31]
In order to make the whole problem easier, you would have to get all the numbers to have the same denominator which would be 60.

1/10 * 6 = 6/60
1/4 * 15 = 15/60
1/5 * 12 = 12/60
2/15 * 4 = 8/60

Now that all the numbers have the same denominator, you would add them to get 41/60.
In conclusion, the answer would be D.
5 0
3 years ago
(2-2) slope intercept form
____ [38]

Answer:

y=mx+b

Step-by-step explanation:

m=slope B= y intercept

(2-2)       y=(mx+b)

8 0
3 years ago
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