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astraxan [27]
3 years ago
8

I need help, please. ​

Mathematics
1 answer:
telo118 [61]3 years ago
8 0

Answer:

a

Step-by-step explanation:

11-9=2 and 2 times 7 is 14, 14 plus 12 is 26 ,and 26=26 is a true statement

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Can you Find the solution of the system of equations?
Lunna [17]

Answer:

x = 3

y = 2

Step-by-step explanation:

multiply by -1 the second equation and add the two equations

7x-7y=7\\4x+7y=26

11x=33

x=33/11

x=3

"y" is calculated:

7(3)-7y=7

21-7y=7

-7y=-14

y=\frac{-14}{-7} =2

Hope this helps

5 0
2 years ago
Lian needs to solve the quadratic equation: x^2 - 4x - 2 = 0. Which statement about how Lian should solve this equation is true?
Ulleksa [173]

Answer:

x = 4.45 or x = - 4.45

Step-by-step explanation:

Here are the steps:

Substitute the values,

4+\sqrt{-4^2-4(1*-2)} ÷ 2 × 1

x = 2 ± √6

x = 4.45 or x = - 4.45

<em>good luck, i hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
7/9 + 5/12 with lcm pls help<br> and give explanation pls
Viefleur [7K]

Answer:

1. 43/36

2. 1/2

Step-by-step explanation:

1. 7/9 + 5/12

= LCM of 9 and 12 is 36

= 28/36 + 15/12

= (28 + 15) / 36

= 43/36

2. 21/24 - 3/8

= LCM of 24 and 8 is 24

= 21/24 - 9/24

= (21 - 9) / 24

= 12/24

= 1/2

3 0
3 years ago
Read 2 more answers
For the inverse variation equation xy=k, what is the constant of variation,k, when x = -3and y=-2
const2013 [10]

Answer:

6

Step-by-step explanation:

xy=k

Value of k ; when ; x = - 3 and y = - 2

Put x = - 3 and y = - 2 into the equation :

(-3)(-2) = k

-3 * - 2 = k

6 = k

The constant of variation k = 6

8 0
3 years ago
Supposef(0) = 2 and 2 ≤ f '(x) ≤ 7for all x in the interval [−5, 5]. determine the greatest and least possible values of f(2).le
IgorC [24]

If the slope of the function is 2, the amount it can change over the interval 0–2 is

... 2×2 = 4 units

If the slope is 7, the amount it can change over the interval 0–2 is

... 2×7 = 14 units


The least possible value of f(2) is 2+4 = 6.

The greatest possible value of f(2) is 2+14 = 16.

7 0
3 years ago
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