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EastWind [94]
3 years ago
10

Find the triangles area drawing not to scale.

Mathematics
1 answer:
Ganezh [65]3 years ago
8 0

Answer:

35 lol

Step-by-step explanation:

a = b*h/2

a = 10*7/2

a = 70/2

a = 35 lol

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write an equation of the line that's passes through the point (1,6) and is parallel to the line whose equation is y= 3x - 5
Alex Ar [27]
Parallel lines have the same slope.
so to find any line, you need a set of points, and a slope.
we already have the slope, being 3.
so, use the equation
y- (y-point)/ x-(x-point)=slope.
y-6. 3
---- = ---- (make it a fraction by puttingitover 1)
x-1. 1
cross multiply.
1(y-6)=3 (x-1)
y-6=3x-3
add 6 to both sides
Final answer: Y=3x+3
7 0
2 years ago
A bakery specializes in cupcakes. Each day, one dozen cupcakes are randomally selected to test for freshness. Which statement be
ziro4ka [17]

Answer:

b) all of the cupcakes in the bakery

Explanation:

in statistics, the population is a group of people/things that are in the same category for collecting data. c) and d) are thus wrong since no data is collected about the other goods or the employees, while a) is wrong because that is just a sample (which helps to test for a large population) and not the actual population.

i hope this helps! :D

3 0
2 years ago
1/4×3/2×8/9 What is the Simplified fraction?
VARVARA [1.3K]

Answer:

1/3

Step-by-step explanation:

1/4×3/2×8/9

Rewriting

8/4 * 3/9 *1/2

Simplify

2 * 1/3 * 1/2

Rewriting

2/2 * 1/3

1 * 1/3

1/3

8 0
3 years ago
Read 2 more answers
Find the area of each geometric figure or product of the polynomial.
Nina [5.8K]
it’s c
Because you do 5n+3 times 5n+3 and you get 25n^2+9
6 0
3 years ago
Given: △PST, m∠S=90°, M∈PT,
swat32

Answer:

m∠P = 70°, m∠T = 20°, m∠SKP = 40° , and m∠MKT = 70°

Step-by-step explanation:

* Lets explain how to solve the problem

- In Δ PST

∵ m∠S = 90°

∴ m∠T + m∠P = 90° ⇒ interior angles of a triangle

∵ m∠SPK/m∠KPT = 5/2

- The ratio between the two angles are 5 : 2 , multiply the parts of the

  ratio by x, where x is a real number

∴ m∠SPK = 5x

∴ m∠KPT = 2x

∵ m∠SPK + m∠KPT = m∠P

∴ m∠P = 5x + 2x = 7x

- In ΔPKT

∵ KM ⊥ PT

∵ MP = Mt

∴ KM is perpendicular bisector of PT

∴ ΔPKT is an isosceles triangle with KP = KT

∵ KP = KT

∴ m∠KPT = m∠T

∵ m∠KPT = 2x

∴ m∠T = 2x

∵ m∠T + m∠P = 90°

∵ m∠P = 7x

∵ m∠T = 2x

∴ 2x + 7x = 90 ⇒ solve for x

∴ 9x = 90 ⇒ divide both sides by 9

∴ x = 10

∵ m∠P = 7x

∴ m∠P = 7(10) = 70°

∴ m∠P = 70°

∵ m∠T = 2x

∴ m∠T = 2(10) = 20°

∴ m∠T = 20°

- In ΔSKP

∵ m∠S = 90°

∵ m∠SPK = 5x = 5(10) = 50°

∴ m∠SKP = 180° - (90° + 50°) = 180° - 140° = 40° ⇒ interior angles of a Δ

∴ m∠SKP = 40°

- In Δ KMT

∵ m∠KMT = 90°

∵ m∠T = 20°

∴ m∠MKT = 180° - (90° + 20°) = 180° - 110° = 70° ⇒ interior angles of a Δ

∴ m∠MKT = 70°

3 0
3 years ago
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