The digit 5 in 4521 has a value that can be found by setting the other digits to zero. It is 500.
The digit 5 in 2615 has a value that can be found by setting the other digits to zero. It is 5.
500 is 100×5.
The digit 5 in 4521 has a value that is <em>100 times</em> the value of the digit 5 in 2615.
Answer:
Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.
The rest of the question:
Which gives the correct order of steps needed to multiply the problem below? "83x39
"
The steps to multiply 83x39
1) multiply the ones 9 times 83 = 9 times 3 + 9 times 80 = 27 + 720 = 747
2) multiply the tens 30 times 83 = 30 times 3 + 30 times 80 = 90 + 2400 = 2490
3) add 747 and 2490 = 747 + 2490 = 3,237
According to the previous steps, the answer is option 3
Multiply the ones. 9 times 83 is 747. Multiply the tens. 30 times 83 is 2,490. Add the products to get 3,237.
Answer:
The relative growth rate is 18.75%.
Step-by-step explanation:
If the world population was 2.560 million in 1950 and 3.040 million in 1960, it means that there was a growth of 480 million people in 10 years. Thus, it is a growth of 18.75%, according to the following calculation:
2,560 = 100
480 = X
(480 x 100) / 2,560 = X
48,000 / 2,560 = X
18.75 = X
Therefore, if this growth rate were to be maintained, in subsequent years the world population would evolve as follows:
1970: 3,040 x 1.1875 = 3,610 million inhabitants
1980: 3,610 x 1.1875 = 4,286 million inhabitants
1990: 4,286.8 x 1.1875 = 5,090 million inhabitants
Answer:
Step-by-step explanation:
It appears to be the last step there that has evaded you. In the second line of work, you can see that what's in each set of parenthesis is exactly the same. Because of this, it is common and can be factored out. What's left is the 4x and the +5:
(5x - 3)(4x + 5)
That's factoring by grouping. It only works with polynomials that have an even number of terms so you can group them together in 2's.
To find that one, just look at the highest exponent. In the given equation that would be 4, so there can be at most 4 zeros in this function.
