NEED HELP ASAP!!! What is the expression in radical form? Show your work. (2x^3y^4)3/7

Help me help help help me help help

grin007 [14]

Answer:

simple, just pretend liek you can write on k ami because i dont

know

Step-by-step explanation:

5 0

4 years ago

A production supervisor at a major chemical company wishes to determine whether a new catalyst, catalyst XA-100, increases the m

zheka24 [161]

Answer:

a. n= 47

b. n= 128

Step-by-step explanation:

Hello!

The objective of this experiment is to test if the new catalyst, XA-100, increases the mean hourly yield of a chemical process, that is known to be μ=750 (pounds per hour) with the current process.

You need to calculate the sample size to estimate the population with determined error margins.

To do so, since you have no population information, only that it is approximately normal distributed, you'll use the Student t statistic to get the sample size.

The formula of the margin of error (d) is:

d= $t_{n-1: 1-\alpha/2}$ * ( $\frac{S}{\sqrt{n} }$ )

I've cleared the sample size of the formula

$n= (S*\frac{t_{n-1; 1-\alpha /2} }{d} )^{2}$

You need a sample size for the t-Student value and a standard deviation, that's why the information of a pilot study with n=5 and S= 19.62 is given.

a)

95% CI

d= 8 pounds

$t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.025} = t_{4;0.975} =2.776$

$n= (19.62*\frac{2.776 }{8} )^{2}$

n= 46.35 ≅ 47

b)

99% CI

d= 5 pounds

$t_{n-1; 1-\alpha/2 } = t_{5-1;1-0.005} = t_{4;0.995} =4.604$

$n= (19.62*\frac{4.604}{8} )^{2}$

n= 127.49 ≅ 128

I hope it helps!

4 0

4 years ago

Find 4 consecutive odd numbers such that twice the sum of the least 2 numbers is 40 less than three times the sum of the greates

ANTONII [103]

4 consecutive odd numbers....x, x + 2, x + 4, x + 6

2(x + x + 2) = 3(x + 4 + x + 6) - 40
2(2x + 2) = 3(2x + 10) - 40
4x + 4 = 6x + 30 - 40
4x + 4 = 6x - 10
4x - 6x = -10 - 4
-2x = - 14
x = -14/-2
x = 7

x + 2 = 7 + 2 = 9
x + 4 = 7 + 4 = 11
x + 6 = 7 + 6 = 13

ur numbers are : 7,9,11,13 <==

4 0

4 years ago

Brainliest* show all work and look at the picture and do all three

hjlf

Answer/Step-by-step explanation:

Formula:

C = 2πr

Note: π = 3.14(About)

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[3] It given that the diameter is 16 ft.

Diameter - a straight line passing from side to side through the center of a body or figure

Radius - Half of Diameter

C = 3.14(16)

= 50.24 ft

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[4] It given that the radius is 7.5 in

Radius - a line segment extending from the center of a circle or sphere to the circumference or bounding surface.

C = 3.14(15)

= 47.1 in

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[5] It given that the radius is 42 m

C = 3.14(84)

= 263.76 m

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As Noted : π is approximately 3.14. Thus the answers are approximately

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Kavinsky

7 0

2 years ago

Match each equation to its factorized version and solution. 24x – 6x2 = 0 2x(x 3) = 0 solution: x = 0, x = -3 14x – 7x2 = 0 6x(4

Archy [21]

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

According to the equation

we have given that the some equation with there values of the x and we have to find and match the correct statement with the given values of x.

So, For this purpose, we know that the

The given quadratic equations are:

A. 24x – 6x^2 = 0 and 2x(3x) = 0 with solution x = 0, x = -3

B. 14x – 7x^2 = 0 and 6x(4 – x) = 0 with solution x = 0, x = 4

C. 2x^2+ 6x = 0 and x(4 – x) = 0 with solution x = 0, x = 4

D. 4x – x^2 = 0 and 7x(2 – x) = 0 with solution x = 0, x = 2

And now we solve it

So,

Take A.

24x – 6x^2 = 0 and 2x(3x) = 0

6x(3 -x) = 0 And 6x^2 = 0

here x = 3 and x = 0.

And

Take B.

14x – 7x^2 = 0 and 6x(4 – x) = 0

7x(2 -x) = 0 And 6x(4 – x)= 0

here x = 2 and x = 4.

And

Take C.

2x^2+ 6x = 0 and x(4 – x) = 0

2x(x +3) = 0 And x(4 – x)= 0

here x = -3 and x = 0.

And

Take D.

4x – x^2 = 0 and 7x(2 – x) = 0

x(4 -x) = 0 And 7x(2 – x)= 0

here x = 4 and x = 0.

So, The correct match of these quadratic equations are
Equation A has a solution x = 3 and x = 0.

Equation B has a solution x = 2 and x = 4.

Equation C has a solution x = -3 and x = 0.

Equation D has a solution x = 4 and x = 0.

Learn more about quadratic equations here

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#SPJ4

7 0

2 years ago