Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Standard equation: (x-h)^2 + (y-k)^2 = r^2
Here, (0-[-6])^2 + (0-[-8])^2 = r^2
Find r: 36 + 64 = 100, so r = 10
Then the desired equation is (x+6)^2 + (y+8)^2 = 10^2
THE ANSWER IS <u>SIN</u><u> </u><u>C</u><u> </u><u> </u><u>SOH</u><u> </u><u>OPPosit</u><u> </u><u>out</u><u> </u><u>of</u><u> </u><u>hypo</u>
2.8 because the tenths place is right after the decimal point.
Answer: 60%
1000÷2=500
Clive: 500-100= 400
Gillian: 500+100= 600 (Because Gillian has 100 more votes than Clive)
