So start with the top one and end w the bottom
YESSSS IT ISSSS CORRECTTT!!!!❤️❤️
Answer:
a) 0.82
b) 0.18
Step-by-step explanation:
We are given that
P(F)=0.69
P(R)=0.42
P(F and R)=0.29.
a)
P(course has a final exam or a research paper)=P(F or R)=?
P(F or R)=P(F)+P(R)- P(F and R)
P(F or R)=0.69+0.42-0.29
P(F or R)=1.11-0.29
P(F or R)=0.82.
Thus, the the probability that a course has a final exam or a research paper is 0.82.
b)
P( NEITHER of two requirements)=P(F' and R')=?
According to De Morgan's law
P(A' and B')=[P(A or B)]'
P(A' and B')=1-P(A or B)
P(A' and B')=1-0.82
P(A' and B')=0.18
Thus, the probability that a course has NEITHER of these two requirements is 0.18.
Hello there!
Evaluate a² for a = -4
The first step we need to do is replace a by -4
So we have (-4)²
Now what you have realize is that we need to multiply -4 by itself twice.
So it should looks like this:
-4 * -4
The rules says that when we have minus * minus, the answer is positive.
So we have -4 * -4 = 16
Answer: 16
I hope this helps!
Please let us know if you have other questions.
#Garebear
