Answer:
No, the reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Step-by-step explanation:
Consider the provided information.
We need to determine that the reference point selected for the properties of a substance have any effect on thermodynamic analysis.
The answer for this question is No.
The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Because in thermodynamic analysis we are deal with the change in the properties.
If we are doing calculation, the reference state chosen is irrelevant as long as we use values in a single consistent array of tables and charts.
Hence, The reference point selected for the properties of a substance does't have any effect on thermodynamic analysis.
Answer:
Step-by-step explanation:
area of side surface=50×20+20×35=1000+700=1700 m²
voume of solid=1700×12=204,00 m³
Answer:
12−3xStep-by-step explanation:
<h3>
There are 2 answers: choice C, choice D</h3>
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Explanation:
32% = 32/100 = 0.32
32% of 400 = 0.32*400 = 400(0.32), which adds onto the original 400 to get 400+400(0.32). This is why choice D is one of the answers.
We can factor out the GCF 400 to go from 400+400(0.32) to 400(1+0.32) which then simplifies to 400(1.32) or just 400*1.32. This shows choice C is the other answer. Using a calculator,
400+400(0.32) = 400 + 128 = 528
400*1.32 = 528
meaning that 400+400(0.32) = 400*1.32
The other answer choices result in other values, showing that they aren't equivalent to 528.
<em>Answer : C: $125.</em>
Hopefully that helps you ! have a good day !
