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Ipatiy [6.2K]
3 years ago
11

What is an equation of the line that passes through the points (8, -3) and (8,4)

Mathematics
1 answer:
weeeeeb [17]3 years ago
3 0

Answer:

x = 8

Step-by-step explanation:

Notice that the x-coordinates of the two points are both 8.  Thus, the points are on the vertical line x = 8.

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The equation of a circle is shown below.
kondor19780726 [428]
The center-radius form<span> of the </span>circle<span> equation is in the format (x – h)</span>2<span> + (y – k)</span>2<span> = r</span>2<span>, with the center being at the point (h, k) and the radius being "r". Therefore, the center is located at point (1, -3) and is located in the fourth quadrant, last option. Hope this answers the question.</span>
3 0
3 years ago
X + 7у = 23 3х + 14у = 48​
Lelechka [254]

Answer:

x + 7у = 23 3х + 14у = 48​

Step-by-step explanation:

x + 7у = 23 3х + 14у = 48​

8 0
2 years ago
Help me please!!!!!!!!
pogonyaev

Answer:

1) 4

2) 1.5

3) 8

4) 1

5) 5

6) 9

Step-by-step explanation:

<h3>1)</h3><h3> √16</h3>

= √(4x4)

= √(4)²

<h3>= 4</h3>

<h3>2)</h3><h3>√2.25</h3>

= √(9/4)

= √(3x3)/(2x2)

= √(3)²/(2)²

= 3/2

<h3>= 1.5</h3>

<h3>3)</h3><h3>6² ÷ 9 x 2 </h3>

= 36 ÷ 9 x 2

= 36 x 1/9 x 2

= 36/9 x 2

= 12/3 x 2

= 4 x 2

<h3>= 8</h3>

<h3>4)</h3><h3>12-2 / 6+4</h3>

= 10/10

<h3>= 1</h3><h3 /><h3>5)</h3><h3>√(16+9)</h3>

= √(25)

= √(5x5)

= √(5)²

<h3>= 5</h3><h3 /><h3>6)</h3><h3>63 ÷ 3² + |2|</h3>

= 63 ÷ 9 + |2|

= 63/9 + |2|

= 21/3 + |2|

= 7 + |2|

<h3>= 9</h3>

3 0
3 years ago
when a number is added to 1/5 of itself, the result is 24. the equation that models this problem is n 1/5 n = 24. what is the va
GuDViN [60]

Let n be unknown number, then 1/5 of this number is 1/5n. When you add these two numbers, you get

n+\dfrac{1}{5} n.

You know that this sum is equal to 24, so

n+\dfrac{1}{5} n=24.

1. Multiply this equation by 5:

5n+n=120.

2. Solve it:

6n=120,\\n=120:6,\\n=20.

Answer: n=20, correct choice is B.

4 0
2 years ago
Read 2 more answers
Enter the set described below:
LenKa [72]

Answer:

  {1, 5, 25, 125, 625}

Step-by-step explanation:

The smallest positive integers that meet the requirement will be ...

  5^0 = 1

  5^1 = 5

  5^2 = 25

  5^3 = 125

  5^4 = 625

As a set, these numbers are {1, 5, 25, 125, 625}.

7 0
2 years ago
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