1) 8 + 4 = -5 + 7
12 = 2
FALSE
2) y = -11x + 4
(0, -7): -7 = -11(0) + 4 ⇒ -7 = 0 + 4 ⇒ -7 = 4 False
(-1, -7): -7 = -11(-1) + 4 ⇒ -7 = 11 + 4 ⇒ -7 = 15 False
(1, -7): -7 = -11(1) + 4 ⇒ -7 = -11 + 4 ⇒ -7 = -7 True
(2, 26): 26 = -11(2) + 4 ⇒ 26 = -22 + 4 ⇒ 26 = -18 False
Answer: C
3) Input Output
0 0
<u> 1 </u> 3
2 <u> 6 </u>
3 9
<u> 4 </u> <u> 12 </u>
5 15
6 <u> 18 </u>
Rule: input is being added by 1, output is 3 times x
4) c = 65h
5) 2x = -6

x = -3
6) 8j - 5 + j = 67
9j - 5 = 67 <em>added like terms (8j + j)</em>
<u> +5</u> <u>+5 </u>
9j = 72

j = 8
7) y = mx + b
<u> -b</u> <u> -b </u>
y - b = mx


I am pretty sure the answer is c. I hope this helps
Answer: there is only one solution
Step-by-step explanation:
Combine like terms by performing the opposite operation of subtracting 4x on both sides of the equation
The 4x's will cross out on the right
4x - 4x = 0x = 0
On the left:
2x - 4x = -2x
Now the equation looks like:
-2x + 3 = 2
Continue to combine like terms by subtracting 3 on both sides of the equation
On the left:
3 - 3 = 0
On the right:
2 - 3 = -1
Equation:
-2x = -1
Isolate x by performing the opposite operation of dividing -2 on both sides of the equation
On the left:
-2x ÷ -2 = 1
On the right:
-1 ÷ -2 = 1/2
x= 1/2
Step-by-step explanation:
1+1=78
Answer:
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%
Step-by-step explanation:
For a normal random variable with mean Mu = 3.2 and standard deviation sd = 0.8 there is a distribution of the sample mean (MX) for samples of size 4, given by:
Z = (MX - Mu) / sqrt (sd ^ 2 / n) = (MX - 3.2) / sqrt (0.64 / 4) = (MX - 3.2) / 0.4
For a sample mean of 3.0, Z = (3 - 3.2) / 0.4 = -0.5
For a sample mean of 3.0, Z = (4 - 3.2) / 0.4 = 2.0
P (3.2 <MX <4) = P (-0.5 < Z <2.0) = 0.6687.
The percentage of samples of 4 fish will have sample means between 3.0 and 4.0 pounds is 66.87%