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3 years ago

NEED HELP ASAP!!!!!

Mathematics

1 answer:

Serggg [28]3 years ago

7 0

Answer:

the correct answer is

The expression that represents Capri’s age is a + 4.

The expression that represents Portia’s age is a – 5.

Solving this equation will give Aziza’s age.

Step-by-step explanation:

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Will give brainliest to correct answer.

kirill [66]

It's going to be kind of crazy, but you need to use Pythagorean's Theorem for this. That will look like this: $(2 \sqrt{x} +1)^2=( \sqrt{x} +1)^2+(2 \sqrt{x} )^2$ . FOIL out the left side to get $4x+4 \sqrt{x} +1$ . FOIL out the first of the 2 expressions on the right to get $x+2 \sqrt{x} +1$ , and the second of the 2 to get 4x. Our equation now looks like this: $4x+4 \sqrt{x} +1=x+2 \sqrt{x} +1+4x$ . Combine like terms to get an equation that still has square roots in it that we have to deal with: $4x-x-4x=-2 \sqrt{x}$ and $x=2 \sqrt{x}$ . We will square both sides to get rid of the square root sign. $x^{2} =2x$ . This is a polynomial now that can be factored to solve for x. Bring the 2x over by subtraction and set the polynomial equal to 0. $x^{2} -2x=0$ . Factor out an x, leaving us with x(x-2)=0. That means that x = 0 or x - 2 = 0 and x = 2. Of course if we are solving for the length of a side we know it can't have a side length of 0, so it must have a side length that is a multiple of 2. x = 2

3 0

3 years ago

Read 2 more answers

From a balloon 915 feet high, the angle of depression to the ranger headquarters is 85°14'. How far is the headquarters from a p

zalisa [80]

<span>tan(85°14') = 915/d
hope this helps

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3 0

2 years ago

Each morning a gardener uses 25 gallons of water from a barrel. Each afternoon, she adds 15 gallons of water to the barrel. By h

mr_godi [17]

Given :

Each morning a gardener uses 25 gallons of water from a barrel.

Each afternoon, she adds 15 gallons of water to the barrel.

To Find :

By how much has the volume of water in the barrel changed after 5 days.

Solution :

Amount of of water used from the barrel per day is :

A = 25 - 15 gallons

A = 10 gallons

Now, volume of water in the barrel changed after 5 days is :

V = A × 5 gallons

V = 10 × 5 gallons

V = 50 gallons

Therefore, volume of water in barrel is changed by 50 gallons.

3 0

2 years ago

9.05 as an improper fraction

EleoNora [17]

Answer:

181/20

Step-by-step explanation:

9.05=9 5/100 = 9 1/20

9*20+1=180+1=181

181/20

4 0

3 years ago

Read 2 more answers

Given that z is a standard normal random variable, find z for each situation. The area between 0 and z is .4750. Answer The area

algol13

Answer:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

We want this probability:

$P(0$

And solving for z we have

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.975,0,1)"

And we got z =1.96

For the next part we want to calculate:

$P(Z>z)= 0.1314$

And we can use the complement rule and we got:

$P(Z>z) = 1-P(Z$

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.8686,0,1)"

And we got z =1.120

For the next part we want to calculate:

$P(Z$

And we can find the value for z with the following excel code:

"=NORM.INV(0.67,0,1)"

And we got z =0.440

6 0

3 years ago