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Varvara68 [4.7K]
3 years ago
13

Points D and E are midpoints of the sides of triangle ABC. The perimeter of the triangle is 48 units.

Mathematics
2 answers:
MatroZZZ [7]3 years ago
5 0

The value of t = 2. <u>Option a)</u> 2 is the correct answer.

<u>Step-by-step explanation:</u>

Perimeter is the sum of three sides of a triangle.

Given that, the points D and E are midpoints of the sides.

Therefore,

side AB= AD+DB

       AB= 3t + 3t = 6t

side BC= BE+EC

       BC= 4t + 4t = 8t

side AC= 7t+6

Perimeter of the triangle= sum of (side AB+side BC+side AC)

48 = 6t+8t+7t+6

48 = 21t+6

t= 42/21

t= 2

zaharov [31]3 years ago
3 0

Answer:

2

Step-by-step explanation:

I just took the test

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3 years ago
EXPERTS PLEASE HELP!!!!!!!!!!!!!!
Arturiano [62]

Answer:

1. D

2. x=65

Step-by-step explanation:

Hi!

Your answer is D because 78 is 120% of x

120% in decimal point is 1.2.

So it's 1.2x is the same as 120% of x

For question 8:

1.2x=78

Isolate x by divide 1.2 on both sides

78/1.2=65

7 0
3 years ago
3(у +8) - 10<br> Distribute property
cupoosta [38]

Answer:

3 y + 14

Step-by-step explanation:

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8 0
3 years ago
The width of rectangle A is the sum of twice a number and 8. The length of the rectangle is 3 times as great as the width. If th
Galina-37 [17]
Formula for perimeter of a rectangle = 2(L + W)
let the number be x
width = 2x + 8
length = 3(2x + 8)
substitute respectively
96 = 2 (2x + 8 + 3(2x + 8)) open the bracket
96 = 2 ( 2x + 8 + 6x + 24) collect like terms
96 = 2 (8x + 32) open the bracket
96 = 16x + 64
collect like terms
96 - 64 = 16x
32 = 16x
divide both sides by 16
32/16 = 16x/16
2 = x
therefore, the width = 2x + 8 = 2(2) + 8 = 4 + 8 = 12.
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4 0
3 years ago
A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat
LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0
2 years ago
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