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maxonik [38]
3 years ago
12

A new car is purchased for 20700 dollars. The value of the car depreciates at 11% per year. What will the value of the car be, t

o the nearest cent, after 11 years?

Mathematics
2 answers:
lozanna [386]3 years ago
7 0

Answer:

5744. 61 cents

Explanation:

after 1 year:

20700×89%=18423

after 2 years:

18423×89%=16396.47

after 3 years:

16396.47×89%=14592.8583

after 4 years:

14592.8583×89%=12987.64389

after 5 years:

12987.64389×89%=11559.00306

after 6 years:

11559.00306×89%=10287.51272

after 7 years:

10287.51272×89%=9155.886323

after 8 years:

9155.886323×89%=8148.738828

after 9 years:

8148.738828×89%=7252.377557

after 10 years:

7252.37757×89%=6454.616026

after 11 years:

6454.616026×89%=5744.608263

~5744.61 (nearest cent)

~

lana [24]3 years ago
7 0

Answer:

$25,047

Step-by-step explanation:

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Dave drove to his friends house and back. It took one hour longer to go there than it did to come back. The average speed on the
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Remark

You know the most about the trip on the way back and the total of the two trips.

Way Back

r = 30 mph

d = distance traveled

t = t - 1 where t = the time to go there which we know nothing about

Total Distance

2d = 25 mph * (t + t - 1)

2d = 25 * (2t - 1)

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Equation coming back

d = 30*(t - 1)

d = 30t - 30

Comment

Since the distances are the same, equate them.

Solution

25t - 12.5 = 30t - 30                     Subtract 25t from both sides

25t - 25t -12.5 = 30t - 25t - 30   Combine like terms

-12.5 = 5t - 30                              Add 30 to both sides

-12.5 + 30 = 5t - 30 + 30             Combine

17.5 = 5t                                       Divide by 5

17.5/5 = t                                      Divide and Switch

t = 3.5

t is the time going there

t - 1 is the time coming back

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The total time is 6 hours.   Answer


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weeeeeb [17]

Answer:

Average Velocity= 70 miles per hour

Step-by-step explanation:

Distance= s

Time = t

s(t)=10t^2

Putting the values

s(2) = 10 (2)^2= 10&4

s= 40

s(5) = 10 (5)^2 = 10*25

S(5)= 250

The average velocity is defined as the rate of change of speed in unit time.

So

Speed= distance/time

Velocity = Speed in a definite direction

Average Velocity= Displacement/ Time

Average Velocity= Change in distance/ Change in time

s(5) - s(2)/ t(5)- t(2)

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