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Setler [38]
3 years ago
8

What is the GCF of 33,55,132

Mathematics
1 answer:
valina [46]3 years ago
7 0
Greatest\ common\ factor\ is\ the\ highest\ number\ by\ witch\ 33\ and\ 55\\and\ 132\ can\ be\ divided\\\\
33:3\\
11:11\\\\
55:5\\
11:11\\\\
132:2\\66:2\\33:3\\11:11
\\\\GCF=3*11=33\\\\Greatest\ common\ factor\ is\ equal\ to\ 33.

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Plz help
jeka94

Answer:

30 miles per hour downstream

20 miles per hour upstream

Step-by-step explanation:

divide 4 by 120 to get the rate downstream

divide 6 by 120 to get the rate upstream

Hope this helps :(

3 0
3 years ago
PLESSE HELPP I NEED HELPPP ASAPPPPPPPP
Akimi4 [234]
D. (2,3)

Explanation:

We already know that x=2, so of we plug in 2 for x, we should get the y value.

Once we plug in 2 for x we should get the equation:

2(2)+3y=13.

Simplify that and we get:

4+3y=13.

Subtract 4 from both sides and we get:

3y=9.

Divide both sides by 3 and we get:

y=3.

This means that your ordered pair should be (2,3).

Hope this helps :)
4 0
3 years ago
4abc + (-9abc) + 10d?
nasty-shy [4]
-5abc+10d will be the answer.
8 0
3 years ago
Read 2 more answers
Mr. Garcia had some blueberries. He sold 2 3/4 kilograms of the blueberries and packed the rest equally into 9 bags. Each bag co
Snezhnost [94]

Answer:

Mr. Garcia had 5 kilograms of blueberries at first

Step-by-step explanation:

to make this easiest, we can imagine that we're undoing mr. garcia's actions.

So, we can start by 'unpacking' mr garcia's bags

we know that each of the nine bags had 1/4 kilograms, so we can multiply 1/4 by 9 to find the collective mass packed into bags

(remember, multiplication is repeated addition. we could also add 1/4 + 1/4 + 1/4... nine times, but this would take a while)

so,

1/4  x 9 = 9/4

(9 = 9/1 [if that is how you're used to multiplying a fraction])

Then, he also sold 2 3/4 kilograms

so, we can add 2 3/4 + 9/4 to find the total mass of the blueberries at first

2 3/4 + 9/4 =  2 + 12/4

(12/4 = 3)

2 + 3 = 5

So, Mr. Garcia had 5 kilograms of blueberries at first

7 0
2 years ago
A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so
mamaluj [8]

Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

7 0
3 years ago
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