3 years ago

The difference of the squares of two consecutive integers is 21. find the integers.

1 answer:

4 0

Let the two integers be x and x+1
(x+1)^2-x^2=21
x^2+2x+1-x^2=21
2x+1=21
2x=20
x=10
then x=10, x+1
10+1=11
the two integers are 10, 11

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Step-by-step explanation:

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Please visit: https://youtu.be/_0Ft9HdNg5c

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