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3 years ago

The difference of the squares of two consecutive integers is 21. find the integers.

1 answer:

4 0

Let the two integers be x and x+1
(x+1)^2-x^2=21
x^2+2x+1-x^2=21
2x+1=21
2x=20
x=10
then x=10, x+1
10+1=11
the two integers are 10, 11

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Hunter-Best [27]

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1 year ago

dalvyx [7]

The first digit may be 1 or 8.

The second digit may be 1, 2, 4, 8.

The third digit may be 1, 3, 5, 7, 9.

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2 years ago

If neither a nor b are equal to zero, which answer most accurately describes the product of (a + bi)(a - bi)?

Scrat [10]

Answer: the correct option is

(D) The imaginary part is zero.

Step-by-step explanation: Given that neither a nor b are equal to zero.

We are to select the correct statement that accurately describes the following product :

$P=(a+bi)(a-bi)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be using the following formula :

$(x+y)(x-y)=x^2-y^2.$

From product (i), we get

$P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.$

So, there is no imaginary part in the given product.

Thus, the correct option is

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2 years ago

Divide. Then, check your work with multiplication. 15.6 / 15

kvv77 [185]

Answer:

the answer is 1.04

Step-by-step explanation:

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2 years ago

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stealth61 [152]

One way:

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Hope you found this helpful :)

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3 years ago

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