Marie will earn $15 per hour at a new job.

Mathematics

2 answers:

denis-greek [22]3 years ago

7 0

What’s the question?

aliya0001 [1]3 years ago

3 0

Answer:can you type the complete question please and thank you

Step-by-step explanation:

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Which equation has no solution? A 2(x+1)=1 B 2(x+1)=2x+2 C 2(x+1)=2x+1 D 2(x+1)=2

Veseljchak [2.6K]

Answer:

C) 2(x+1)=2x+1 ( No Solution )

Step-by-step explanation:

$2(x+1)=1\\\cfrac{2\left(x+1\right)}{2}=\frac{1}{2}\\x+1=\cfrac{1}{2}\\ x+1-1=\frac{1}{2}-1\\\boxed{x=-\frac{1}{2}}$

$2(x+1)=2x+2\\2x+2=2x+2\\2x+2-2=2x+2-2\\2x=2x\\2x-2x=2x-2x\\0=0$

$2(x+1)=2x+1 \\2x+2=2x+1\\2x+2-2=2x+1-2\\2x=2x-1\\2x-2x=2x-1-2x\\0=-1\\\boxed{No\:Solution}$

$2(x+1)=2\\\cfrac{2\left(x+1\right)}{2}=\cfrac{2}{2}\\x+1=1\\x+1-1=1-1\\x=0$

4 0

2 years ago

Solve for x.

Nonamiya [84]

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\text{use distributive property}\\\\-\dfrac{2}{\not3_1}\cdot\not3^1x+\dfrac{8}{3}+3x=\dfrac{5}{6}\\\\-2x+3x+\dfrac{8}{3}=\dfrac{5}{6}\ \ \ \ |-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8}{3}\\\\x=\dfrac{5}{6}-\dfrac{8\cdot2}{3\cdot2}\\\\x=\dfrac{5}{6}-\dfrac{16}{6}\\\\\boxed{x=-\dfrac{11}{6}}$

Other method:

$-\dfrac{2}{3}(3x-4)+3x=\dfrac{5}{6}\ \ \ \ |\cdot6\\\\2(-2)(3x-4)+18x=5\\\\-4(3x-4)+18x=5\ \ \ \ |\text{use distributive property}\\\\-12x+16+18x=5\ \ \ \ |-16\\\\6x=-11\ \ \ \ |:6\\\\\boxed{x=-\dfrac{11}{6}}$

7 0

3 years ago

Read 2 more answers

Y=(2x-3)^5(2-x^4)^3 differentiate the function please

BARSIC [14]

$\bf y=(2x-3)^5(2-x^4)^3\\\\
-------------------------------\\\\
\cfrac{dy}{dx}=\stackrel{\textit{product rule}}{[5(2x-3)^4\cdot 2(2-x^4)3]~~+~~[(2x-3)^5[3(2-x^4)^2(-4x^3)]]}
\\\\\\
\cfrac{dy}{dx}=10(2x-3)^4(2-x^4)^3~~-~~12x^3(2x-3)^5(2-x^4)^2
\\\\\\
\cfrac{dy}{dx}=\stackrel{\textit{common factor}}{2(2x-3)^4(2-x^4)^2}~[5(2-x^4)-6x^3(2x-3)]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2~[10-5x^4-12x^4+18x^3]
\\\\\\
\cfrac{dy}{dx}=2(2x-3)^4(2-x^4)^2(10-17x^4+18x^3)$