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3 years ago

Marie will earn $15 per hour at a new job.

Mathematics

2 answers:

denis-greek [22]3 years ago

7 0

What’s the question?

aliya0001 [1]3 years ago

3 0

Answer:can you type the complete question please and thank you

Step-by-step explanation:

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I do not know how to solve this problem or know what to do with the exponents

horsena [70]

K, remember
(ab)/(cd)=(a/c)(b/d) or whatever
also
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}= \frac{1}{x^m}$
and
$x^ \frac{m}{n}= \sqrt[n]{x^m}$
and
$( \frac{x}{y} )^m= \frac{x^m}{y^m}$
and
$(x^m)^n=x^{mn}$
and
(a/b)/(c/d)=(a/b)(d/c)=(ad)/(bc)

so
$( \frac{-7x^ \frac{3}{2} }{5y^4} )^{-2}$ =
$( \frac{-7}{5} )^{-2}( \frac{x^ \frac{3}{2} }{y^4} )^{-2}$ =
$( \frac{(-7)^{-2}}{5^{-2}} )( \frac{(x^ \frac{3}{2})^{-2} }{(y^4)^{-2}} )$ =
$( \frac{ \frac{1}{(-7)^2} }{ \frac{1}{5^2} } )( \frac{x^ \frac{-6}{2} }{y^{-8}} )$ =
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{(x^{-3}) }{\frac{1}{y^8}} )$
$( \frac{ \frac{1}{49} }{ \frac{1}{25} } )( \frac{\frac{1}{x^3} }{\frac{1}{y^8}} )$ =
$(\frac{25}{49} )( \frac{y^8}{x^3}$ =
$\frac{25y^8}{49x^3}$

4 0

3 years ago

PLEASE HELP ME ASP! Brainlist and 25 points!

Bezzdna [24]

Answer:

Answer is in the explanation

Step-by-step explanation:

I don't know exactly word from word what your choices look like...

but I can describe per each box what happened in my own words:

First box: They multiply first equation by 3 and the second equation by 2 to obtain the equations in that first box.

Second box: They subtracted the two equations in the first box to obtain 1x+0y=2 which means 1x=2 or x=2 (this is called solving a system by elimination

Third box: They used their first original equation (before the multiplication manipulation) and plug in the value they got for x which was 2 giving them 3(2)-2y=10

Fourth box: They simplified the equation 3(2)-2y=10 by performing the multiplication 3(2) giving them 6-2y=10

Fifth box: They subtracted 6 on both sides giving them -2y=4

Sixth box: They divided both sides by -2 giving them y=-2

I will summarize then what I wrote above:

1st box: Multiplication Property of Equality

2nd box: Elimination

3rd box: Substitution (plug in)

4th box: Simplifying

5th box: Subtraction Property of Equality

6th box: Division Property of Equality

4 0

3 years ago

Rewrite the formula to find w.

sveta [45]

Answer:

P / 30 - 21= 9

2w = 9

w = 4.5

This should be the answer

4 0

3 years ago

The fourth term of an arithmetic

yulyashka [42]

Answer:

Step-by-step explanation:

Given AP where:

a₄ = 2a₂ - 1
a₆ = 7

To find

a₁ = ?

Since

a₄ = a₁ + 3d
a₂ = a₁ + d
a₆ = a₁ + 5d

Initial equations will change as:

a₁ + 3d = 2(a₁ + d) - 1 ⇒ a₁ + 3d = 2a₁ + 2d - 1 ⇒ a₁ = d + 1
a₁ + 5d = 7 ⇒ a₁ = 7 - 5d

Comparing the above:

d + 1 = 7 - 5d
6d = 6
d = 1

Then:

a₁ = d + 1 = 1 + 1 = 2
a₁ = 2

The first term is 2

5 0

3 years ago

Whats the is the value

telo118 [61]

Can't see the graph can you make it more clear?

5 0

3 years ago