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Virty [35]
3 years ago
7

An airport limousine can accommodate up to four passengers on any one trip. The company will accept a maximum of six reservation

s for a trip, and a passenger must have a reservation. From previous records, 45% of all those making reservations do not appear for the trip. Answer the following questions, assuming independence wherever appropriate. (Round your answers to three decimal places.)
(a) If six reservations are made, what is the probability that at least one individual with a reservation cannot be accommodated on the trip?
1

(b) If six reservations are made, what is the expected number of available places when the limousine departs?
2 places

(c) Suppose the probability distribution of the number of reservations made is given in the accompanying table.

Number of reservations 3 4 5 6
Probability 0.09 0.25 0.32 0.34
Let X denote the number of passengers on a randomly selected trip. Obtain the probability mass function of X.

x 0 1 2 3 4
p(x)
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0

Answer:

i think c

Step-by-step explanation:

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P(X=x) = p(1-p)^{x-1}\\

The problem asks us to find the probability of the first success on the 4th trial (given that the first subject to be a universal blood donor will be the fourth person selected)

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Substituting these parameters in the formula and solving it, we get:

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Therefore, the probability that the first subject to be a universal blood donor is the fourth person selected is 0.0428 or 4.28%

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Step-by-step explanation:

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