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3 years ago

Which one is false ????

Mathematics

1 answer:

fenix001 [56]3 years ago

4 0

Answer:

Step-by-step explanation:

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25 POINTS AVAILABLE

myrzilka [38]

Answer:

$\large\boxed{1.\ (-3, 0),\ r = 3}\\\boxed{2.\ (x+4)^2+(y-3)^2=36}\\\boxed{3.\ (x-2)^2+(y-1)^2=(\sqrt{34})^2}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

1. We have the equation:

$(x+3)^2+y^2=9\\\\(x-(-3))^2+(y-0)^2=3^2$

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2. We have the center (-4, 3) and the radius r = 6. Substitute:

$(x-(-4))^2+(y-3)^2=6^2\\\\(x+4)^2+(y-3)^2=36$

3. We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

7 0

3 years ago

4(x-3)-5(x+1)=3 What math property do I use?

34kurt

you use the distributive property

hopes this helps

6 0

2 years ago

Read 2 more answers

An architect is making a scale model of a building. The model is 18.5 inches wide and 36.5 inches tall. If the actual building i

Nastasia [14]

Answer:

The height of the building is 730 feet.

Step-by-step explanation:

370 x 12 = 4,440 inches

4,440 ÷ 18.5 = 240 inches

240 x 36.5 = 8,760 inches = 730 feet

3 0

3 years ago

Please help me with both parts?

Neko [114]

I'm willing to help you with both parts

4 0

3 years ago

What is the difference between -4 and 6

Sindrei [870]

<em> $answer = - 10 \\ solution \\ - 4 - 6 \\ = - 10 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$ </em>

5 0

3 years ago

Read 2 more answers