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geniusboy [140]

2 years ago

8

Mr. Smith paid $232,300 for his home and $33,560 for his car. Mr. Lewton paid a total of $282,106 for his home and car combined.

How much more money did Mr. Lewton pay than Mr. Smith for a home and car?

1 answer:

tester [92]2 years ago

4 0

Mr lewton paid more for his here’s why he paid about 16,246 dollars more for his car

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Find the GCF (greatest common factor) of 8 and 7.

FrozenT [24]

Answer: Its 1

Step-by-step explanation:

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2 years ago

What is 0.003 is 1/10of

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0.003 is 1/10 of 0.03.
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3 years ago

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Jim needs to divide 762 coupon books equally among 9 stores. In which place is the first digit of the quotient? Select the word

nevsk [136]

Answer:

ones

Step-by-step explanation:

It is given that Jim wants to divide 762 coupons equally among 9 stores.

So dividing 762 by 9, we get

$=\frac{762}{9}$

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2 years ago

Susan was supposed to use 5/4 of a cup of butter

ElenaW [278]

Answer:

$a.\ \dfrac{3}{5}$

Step-by-step explanation:

We can see the fractions $\frac{5}{4}$ and $\frac{3}{4}$ of cups.

It can be seen that denominator has 4 i.e. the fraction $\frac{1}{4}$ .

Let us suppose, a unit is equal to $\frac{1}4$ of a cup.

Susan was supposed to use $\frac{5}{4}$ of a cup.

i.e. 5 units of butter was to be used.

But, actual recipe has only 3 units of butter.

$\text{Fraction of butter used} = \dfrac{\text{Units of butter used}}{\text{Unit of butter Susan was supposed to use}}$

a. $\text{Fraction of butter used} = \dfrac{3}{5}$

Alternatively, we could have directly divided the given fractions:

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4 0

3 years ago

The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh

sp2606 [1]

<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>The height of a ball thrown into the air after t seconds have elapsed is:</u></em>

$h = -16t^2 + 40t + 6$

<em><u>What is the first time, t, when the ball will reach a height of 20 feet?</u></em>

Substitute h = 20

$20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0$

<em><u>Solve by quadractic formula</u></em>

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-20,\:c=7$

$t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084$

Rounding off we get,

t = 2.08 , t = 0.42

Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds

4 0

3 years ago