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BartSMP [9]
3 years ago
8

Hey I need help with the bottom part?

Mathematics
1 answer:
weqwewe [10]3 years ago
3 0
All of the answers?
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-9 is less than or equal to x and 7 is greater than or equal to x
const2013 [10]
Plot a point at "-9" and the other at "7". Both dots will be shaded in.
8 0
3 years ago
For each sequence shown find the<br> growth factor or rate of change.<br> 5, 15, 25, 35, 45
olga nikolaevna [1]
The numbers are increasing by positive 10 each time. So the rate of change is 10.
6 0
3 years ago
Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9
NeTakaya
<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}

Now you can rewrite it as:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}

Next, multiply:

(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}

Next, divide:

(\frac{f}{g})(x)=(x+2)^2

And lastly, simplify:

  • A good tip: (x+y)^2=x^2+2xy+y^2

(\frac{f}{g})(x)=x^2+4x+4

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

7 0
4 years ago
PLEASE HELP I HAVE NO IDEA WHAT IM DOING!!!
algol13

Answer: 28.26


Step-by-step explanation:

What your looking for is called the annulus (or the difference of two concentric circles). You can find the annulus by subtracting the area of the inner circle from the area of the outer circle. Volume of a circle= πr²

You are given the diameter in these problems, so you need radius.

For the first circle (8 in one) :

8/2=4    r=4

A=3.14(4)²

A=50.24

For the second one (10 in one) :

10/2=5   r=5

A=3.14(5)²

A=78.5

To find the measure of the annulus, you subtract those numbers, getting 28.26


8 0
3 years ago
Describe how k affects the graph of the function f(x)= -3/5(10)^x
Shalnov [3]

Answer:

1437.33

Step-by-step explanation:

8 0
3 years ago
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