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bixtya [17]
3 years ago
6

Which of the following is the product of x-2 and x-3 from the FOIL method?

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

FOIL is an ancronym to help you remember to multiply each term. basically it's for people who can't distribute good


anwya


FOIL stands tells you which terms to mulitply, you then add the results up

F=First terms

O=Outer terms
I=Inner terms

L=Last terms



so

(x-2)(x-3)

First: x times x = x^2

Outer: x times -3=-3x

Inner: -2 times x=-2x

Last: -2 times -3=6


now add them all up

x^2-3x-2x+6=x^2-5x+6



answer is the second option

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This is due today i would appreciate it a lot if smn could help me with it :/
Vesnalui [34]

Answer:

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x        1         2         3         4

y       5        8          11        14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

                                 = 3/1

                                  = 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

y\:=\:\frac{5}{3}x+3

comparing with the slope-intercept form of a linear function

y = mx+b     where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

y\:=\:\frac{5}{3}x+3

y\:=\:\frac{5}{3}\left(0\right)+3

y = 0+3

y = 3

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1  = 3

The rate of change of function 2 = 5/3

  • Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

  • Hence, function 2 has a greater initial value.

8 0
3 years ago
Subtract. (4x2+8x−2)−(2x2−4x+3) Enter your answer, in standard form, in the box.
Crazy boy [7]

the answer is 2x2+12z-5 (its also in the picture)

3 0
3 years ago
Which of the following exponential functions represents the graph below?
mario62 [17]

Answer:

the graph corresponds to function "D"  f(x)=3\,(\frac{1}{5} )^x

Step-by-step explanation:

Since the graph shown corresponds to an exponential "decay" (the function decreases as we move from left to right), the base of the exponent has to be a number smaller than 1 (one). So we examine the only two options that give such (options C and D which have fractions as the base - 1/3 and 1/5 respectively)

From there, we analyze which of the two functions satisfies the crossing of the y-axis at (0,3) which is clearly shown in the graph:

We study both:

function C at x = 0 gives:

f(x)= 5\,(\frac{1}{3})^x\\f(0)=5\,(\frac{1}{3})^0 \\f(0)=5\,(1)\\f(0)=5

while function D at x = 0 gives:

f(x)= 3\,(\frac{1}{5})^x\\f(0)=3\,(\frac{1}{5})^0 \\f(0)=3\,(1)\\f(0)=3

Therefore, the graph corresponds to function "D"

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kobusy [5.1K]
I hope this helps you


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