Answer:
6 cm (Option A)
Step-by-step explanation:
<u>GIVEN :-</u>
- ΔPQR whose area is 32 cm² & has base QR.
- ΔABC whose area is 8 cm² & has base BC = 3 cm
- ΔPQR is an enlarged figure of ΔABC.
<u>TO FIND :-</u>
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
Lets say there are two triangles ΔABC & ΔXYZ , who are similar to each other.

<u>SOLUTION :-</u>
In the question it's given that ΔPQR is an enlarged figure of ΔABC.
⇒ ΔPQR is similar to ΔABC.

Root squaring both the sides ,


Multiplying both the sides by 3 ,

