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2 years ago

14

The experimental probability of rain in a certain town is 20 percent. In the next 45 days, how many days can one expect it to ra

in?

1 answer:

Hatshy [7]2 years ago

8 0

9.

hope this helps :)

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Fraction strip for 1/4, 2/8,3/12

Brilliant_brown [7]

4/16, 5/20, 6/24, 7/28, 8/32...

7 0

2 years ago

Solve for p:<br><br> p – 23 = -3<br> A. p = 20<br> B. p = -20<br> C. p = -26<br> D. p = 69

Alekssandra [29.7K]

P-23=-3
+23 +23

P=20

so the answer is A

6 0

1 year ago

Help me with this pls

kobusy [5.1K]

Answer:

C.)-5

Step-by-step explanation:

y2-y1/x2-x1

(-9,6) (-6,-9)

-9-6=-15

-6-(-9)=3

-15/3=-5

4 0

2 years ago

Read 2 more answers

For the following exercises, evaluate the function f at the values f(−2), f(−1), f(0), f(1), and f(2)

MatroZZZ [7]

Answer:

See below. <u><em>I assume that (x) = 8x2 - 7x + 3 is really (x) = 8x^2 - 7x + 3</em></u>

Step-by-step explanation:

Substitute the value of x given in f(x) into the equation f(x) = 8x^2 - 7x + 3

For example, f(0) would be f(0) = 8(0)^2 - 7(0) + 3. f(0) = 3

f(-2) would be f(-2) = 8(-2)^2 - 7(-2) + 3.

= 8*4 + 14 +3

= 32 + 17 therefore f(-2) = 49

<u>x</u> <u>f(x)</u>

-2 49

-1 18

0 3

1 4

2 21

4 0

1 year ago

If a certain cannon is fired from a height of 8.8 meters above the ground, at a certain angle, the height of the cannonball ab

Dennis_Churaev [7]

Answer:

It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

$h(t)=-4.9t^2+30.5t+8.8$

We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

$-4.9t^2+30.5t+8.8=0$

Multiply both sides by 10.

$-49t^2+305t+88=0$

For a quadratic equation of the form $ax^2+bx+c=0$ the solutions are: $x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Substitute a = -49, b = 305 and c=88

$t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}$

Ignore the negative value of t as time can't be a negative number.

Thus,

$t=\frac{305+\sqrt{110273}}{98}\approx6.50$

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

6 0

2 years ago