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Readme [11.4K]
3 years ago
10

Frank, a scuba diver, requires 60% of the light from the surface of the water for his

Mathematics
2 answers:
muminat3 years ago
8 0

Answer:

you do 2*23 to get that you lose 46% light intensity which means frank will not be able to see because the intensity is 54%

Step-by-step explanation:

denpristay [2]3 years ago
7 0
Sbainsisbxkxbzkzbajsjsja bcjxoxososkakaka
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........................................................
irakobra [83]
Bbbbnendjxndnnfrijdndjndneieir
8 0
3 years ago
Which value of y makes the equation 55/y = 5 true?
Georgia [21]

Answer:

11

Step-by-step explanation:

55/11=5

4 0
3 years ago
A brace for a shelf has the shape of a right triangle. Its hypotenuse is 10 inches long and the two legs are equal in length. Ho
vagabundo [1.1K]
This is a classic example of a 45-45-90 triangle: it's a right triangle (one angle of 90) & two other sides of the same length, which means two angles of the same length (and 45 is the only number that will work). With a 45-45-90 triangle, the lengths of the legs are easy to determine:
45-45-90
1-1-sqrt2
Where the hypotenuse corresponds to sqrt2.
Now, your hypotenuse is 10.
To figure out what each leg is, divide 10/sqrt2 (because sqrt2/sqrt2 = 1, which is a leg length in the explanation above).
Problem: you can't divide by radicals. So, we'll have to rationalize the denominator:
(10•sqrt2)/(sqrt2•sqrt2)
This can be rewritten:
10sqrt2/sqrt(2•2)
=10sqrt2/sqrt4
=10sqrt2/2
=5sqrt2 Hope this helps!!
3 0
3 years ago
Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π ​ )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac
uranmaximum [27]

One way to do this is to notice

\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4

Then

\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}

We have

\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}

and since \tan x has a period of \pi,

\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1

and so

\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3

7 0
3 years ago
Please help!!! Imagine is attached
Paul [167]

Answer:

They're both parabolas.

One is a parabola opening up (blue), the other one is opening down.

Step-by-step explanation:

In dutch, we call them what can be translated as  mountain-parabolas and valley-parabolas.

I also saw the terms "concave up" and "concave down".

8 0
3 years ago
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