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Anna007 [38]
3 years ago
13

Find fog(x) when f(x) = 2x² + x and g(x) = 3x + 2

Mathematics
1 answer:
nekit [7.7K]3 years ago
6 0
For fog or f(g(x)), plug g(x) into f(x):

2(3x+2)²+x

Then simplify:

2( (3x+2)(3x+2) )+x

2( 9x²+12x+4 )+x

18x²+24x+8 +x

18x²+25x+8

Then you can simplify this further using factoring methods to:

(2x+1)(9x+8)

Hope this helps!! :)

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Simplify and evaluate

9) 6x^2 - 27 + 4x^3

10) -7x2 - 5x + 9
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What is the ratio of 2:3 of 52.20
shutvik [7]
I don't think there is a ratio for that I have only herd of stuff like "What is the ratio of 5 to 3.
8 0
3 years ago
On average,Shane drinks 1/2 of a 6-ounce of water in 2/3 hour.How much water does she drinks in an hour.Show work
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Answer:

4.5 ounces

Step-by-step explanation:

First dived 3 by 2 to figure out how much water she drinks in 1/3 of a hour.  

Second, you take the answer 1.5 ounces per 13 of an hour and multiply it by 3.

Lastly, you get your answer 4.5 ounces of water in a hour.

1. 3 / 2 = 1.5

2. 1.5 x 3 = 4.5

7 0
3 years ago
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First you to find the worksheet and download it<br> plase I need help
Goshia [24]

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = 3^{x + 2}

The asymptote is given as x → -∞, f(x) = 3^{x + 2} → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = 3^{0 + 2} = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = 5^{1  - x}

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = 5^{1  - 0} = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = 2^{x + 3} - 1

The asymptote is 2^{x + 3}  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  2^{0 + 3} - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, 2^{x + 3} - 1 = 0

2^{x + 3} = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2

The asymptote is \left (\dfrac{1}{2} \right)^{x - 2} → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6

The y-intercept is (0, 6)

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2 years ago
A test is worth 140 points. Ten percent of those points are from one short-answer question. How many points is the short-
Mashutka [201]
The answer is 14. Since 140 x .10 = 14.
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