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3 years ago

Solve the system of equations and choose the correct answer from the list of options d+e =12 -d+e=-8

Mathematics

1 answer:

Svetllana [295]3 years ago

7 0

D + e = 12
-d + e = -8
---------------
2e = 4
e = 2

d + e = 12
d + 2 = 12
d = 10

Answer: (10,2)

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Pls help. Evaluate the expression 3.14(a2 + ab) when a = 3 and b = 4. (Input decimals only, such as 12.71, as the answer.)

givi [52]

3.14(3(2) + 3(4))
3.14( 6 + 12)
3.14(18)
=56.52

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3 years ago

Select the statement that correctly compares two numbers.

shepuryov [24]

D because it’s the same

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3 years ago

When we test Upper H 0: muequals0 against Upper H Subscript a: mugreater than0, we get a P-value of 0.03. a. What would the

Anastasy [175]

Answer:

(a) The null hypothesis will be rejected.

(b) Type I error

Step-by-step explanation:

The hypothesis provided is:

$H_{0}: \mu = 0\\ H_{a} : \mu > 0$

The p-value of the test obtained is 0.03

(a)

Decision rule for hypothesis testing, based on p-value, states that if the p-value is less than the significance level (α) then the null hypothesis is rejected and vice versa.

The significance level is α = 0.10

Then,

$p-value = 0.03 < \alpha = 0.10$

Thus, the null hypothesis will be rejected.

Conclusion:

The null hypothesis is rejected stating that the value of μ is more than 0.

(b)

If the decision in (a) is an error, i.e. the null hypothesis is rejected when in fact it is true, this type of error is known as type I error.

(c)

The significance level is α = 0.01

Then,

$p-value = 0.03 > \alpha = 0.01$

Thus, the null hypothesis will not be rejected.

Conclusion:

The null hypothesis was not rejected stating that the value of μ is 0.

If this decision is an error, i.e. the null hypothesis was not rejected when in fact it is false, this type of error is known as type II error.

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3 years ago

Express 60 as the product of its prime factors in ascending order and give your answer in index form

Allisa [31]

Answer:

${2}^{2}$ , 3, 5 are the prime factors of 60.

Step-by-step explanation:

$60 = 2 \times 2 \times 3 \times 5 \\ = {2}^{2} \times 3 \times 5 \\$

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3 years ago

Help help help if u can answer this I’ll mark u brainliest (6) (the one in the middle)

Hoochie [10]

You just have to plug in each thing:

So f(0):

3(0)^2 - 4 = -4

so its not A

f(-2) and f(2):

3(-2)^2 - 4

3(2)^2 -4

now we don't even have to calculate these, anything to the power of an even number is a positive number so -2^2 and 2^2 both equal 4

B is correct, so you can do the others if you want to check, but if B is true the others shouldn't be true.

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3 years ago